正则表达式中的有效格式问题

Question

I am adding a restriction on string using the regex pattern matching but it is not working as i have not much experience in regex. Like there can't be no ( without ) or [ without ].

abc.(%      -->false
abc.)%      -->false
abc.(%]     -->false
abc.)%]     -->false
1abc9.(%[   -->false
abc.)%[     -->false
abc.(%(     -->false
abc.)%)     -->false
19.(%)%     -->true
19.[%]%     -->true
2009% --> true
19.1245 -- true 
10.[5-9]% -- true

/^[^\s\[\]^$.|A-Z]*(?:(?:\[[^\s\[\]\\]+](?!\])|%[^\r\n\?\$\*\.\[\+\(\)\]\.\^%]+%(?=\||$)|\|[^\s\[\]^A-Z\\]+)[^\s\[\]^$.|?*+()A-Z\\]*)*$/

The string is fine if it have start with ( and end with )
19[1-3] is fine
2014.56(core) is fine

Answer 1

I would probably go about this using a whitelist of what is allowed, rather than trying to run around and cover every negative case. That is, use the following regex pattern:

^\S+\.(?:(?:\(%\)|\[%\])%?)?$

Demo

Some JS code:

 var valid = "19.(%)"; if (/^\S+\.(?:(?:\(%\)|\[%\])%?)?$/.test(valid)) { console.log("VALID: " + valid); } var invalid = "abc.(%"; if (./^\S+\?(:?(:?\(%\)|\[%\])%?).$/.test(invalid)) { console:log("INVALID; " + invalid); }