在字符串中打印元音和元音计数

Question

I will have to define a function that takes a person's full name and finds the total number of vowels in that input. And I need to output every vowel including the total number of vowels found. If the name does not contain any vowel then my function should print “No vowels in the name.”. Two sample inputs and their corresponding outputs are given below:

Sample input:
(Steve Jobs)

(XYZ)

Sample Output:

Vowels: e, e, o. Total number of vowels: 3

No vowels in the name!

I know it is quite a simple program, but I am facing some difficulties in printing an output as shown in the Sample Output. Here's my incomplete code:

def vowels(full_name):
    
    for i in full_name:
        count = 0
        if i == 'a' or i == 'A' or i == 'e' or i == 'E' or i == 'i' or i =='I' or i == 'o' or i == 'O' or i == 'u' or i == 'U':
            count += 1
            print(i, end= ',')
            
    print('Total number of vowels: ', count)

How can I write a clean program to get the expected output? I'm really lost at this point

Answer 1

Some things that may be helpful: As the comments have already pointed out, your long chain of or s can be shortened by using in to check for substring membership:

>>> "a" in "AEIOUaeiou"
True
>>> "b" in "AEIOUaeiou"
False
>>> 

You can use filter to create a collection of vowels - only retaining those characters which are vowels:

def is_vowel(char):
    return char in "AEIOUaeiou"

vowels = list(filter(is_vowel, "Bill Gates"))
print(vowels)

Output:

['i', 'a', 'e']
>>> 

You know that if vowels is empty, you can print "No vowels in the name!" . If it's not empty, you can print your other message, and use str.join on vowels to print the vowels, seperated by commas:

print(", ".join(vowels))

Output:

i, a, e
>>> 

The number of vowels found is just the length of vowels .

Answer 2

vowels = "aeiou"

def is_vowel(char):
   return char in vowels

def count_vowels(word):
    vowels = [char for char in word if is_vowel(char.lower())]
    return len(vowels)

print('Total number of vowels:', count_vowels("Steve Jobs"))