Python for 循环没有遍历所有元素？ 它只取第一个元素

Question

I am trying to scrape the data from naukri.com, here I am trying to scrape the location details for each recruiter visible on the page.

The code I am writing is:

def sol7(url):
    driver = webdriver.Chrome(r'C:\Users\Rahul\Downloads\chromedriver_win32\chromedriver.exe')
    driver.maximize_window()
    driver.get(url)
    
    #getting link of recruiters
    recruiters_tag = driver.find_element_by_xpath("//ul[@class='midSec menu']/li[2]/a")
    driver.get(recruiters_tag.get_attribute('href'))
    
    #search and click for data scientist
    driver.find_element_by_xpath("//input[@class='sugInp']").send_keys('Data science')
    driver.find_element_by_xpath("//button[@id='qsbFormBtn']").click()
    
    
    highlight_table_tag = driver.find_elements_by_xpath("//p[@class='highlightable']")
    print(len(highlight_table_tag))
    for i in highlight_table_tag:
        try:
            print((i.find_element_by_xpath("//small[@class='ellipsis']")).text)
        except NoSuchElementException:
            print('-')

1st I have extracted all recruiters details in list highlight_table_tag. highlight_table_tag includes all the elements on the page however the loop only takes the 0th element of my list. I want to scrape the location in such a way, if the location tag is not there in each element of highlight_table_tag then print '-' instead.

Please help!!!!

Answer 1

While xpathing child elements use. in front of the xpath otherwise you will be getting it from root node. Which ends up with 1 element everytime.

print((i.find_element_by_xpath(".//small[@class='ellipsis']")).text)