C++ 是否将 char 指针视为 c 样式字符串？

Question

Does C++ treat char pointers as c-style strings?

int main(int argc,char* argv[])
{
    if (argv[1] == "-d")
    {

    }
}

argv[1] contains a char pointer, how is the statement argv[1] == "-d" not causing the compiler to throw an error because "d" is a string whereas argv[1] is a pointer to a char value

Answer 1

because "d" is a string whereas argv[1] is a pointer to a char value

That's where you're kind of wrong friend.

argv[1] is in this case a char* like you said.

"-d" is a const char[3] ( -d plus the null terminator), this array can decay to a pointer which means == compiles.

As pointed out in the comments though, this will probably not do what you expect it to do. This will do a pointer comparison and not a comparison of the actual strings. You'll need to use strcmp for that.