根据 pandas dataframe 中的条件获取最大值和最小值

Question

I have a dataframe like this

count	A	B	Total
yes	4900	0	0
yes	1000	1000	0
sum_yes	5900	1000	0
yes	4000	0	0
yes	1000	0	0
sum_yes	5000	0	0

I want result like this that is calculate max of column A and B only for rows where 'count' = 'sum_yes' if value of B =0 otherwise calculate minimum

count	A	B	Total
yes	4900	0	0
yes	1000	1000	0
sum_yes	5900	1000	1000
yes	4000	0	0
yes	1000	0	0
sum_yes	5000	0	5000

I have tried this so far:

df['Total'] = [df[['A', 'B']].where(df['count'] == 'sum_yes').max(axis=0) if 
                   'B'==0 else df[['A', 'B']]
                   .where(df['count'] == 'sum_yes').min(axis=0)]

But I am getting ValueError The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all()

Any idea how to solve this

Answer 1

You can use numpy.where :

new_values = np.where((df["count"] == "sum_yes") & (df.B == 0),
                       df.loc[:, ["A", "B"]].max(1),
                       df.loc[:, ["A", "B"]].min(1),
                      )

df.assign(Total = new_values)


     count     A     B  Total
0      yes  4900     0      0
1      yes  1000     0      0
2  sum_yes  5900  1000   1000
3      yes  4000  1000   1000
4      yes  1000     0      0
5  sum_yes  5000     0   5000