如何在 arduino 中将八进制数转换为十进制数？

Question

My problem is converting octal number to decimal number print using Arduino functions.

int octalNum = 33;
int decimalNumb = 0;
void setup()
{
    Serial.begin(9600);
}

void loop()
{
    Serial.println("Octal Number = "+octalNum);
    Serial.println("Decimal Number = "+decimalNumb);
}

Answer 1

Use the format parameter described in reference manual for println :

Serial.println(analogValue, OCT);  // print as an ASCII-encoded octal

Something like:

Serial.print("Octal Number = ");
Serial.println(octalNum , OCT);

Output:

Octal Number = 41

as the octal value of the decimal number 33 is 41 .
If instead you meant defining octalNum using an octal constant, in the first place, just remember that octal constants are defined inserting an heading 0 :

int octalNumber = 033; // decimal 27

---

Please note how OctalNum is just stored as an integer, and this has nothing to do with the way is printed later.

Answer 2

int octalNum = 33;
int decimalNumb = 0;
void setup()
{
  Serial.begin(9600);
}

void loop()
{
      Serial.println("Octal Number = "+octalNum);
     Serial.println("Decimal Number = "+octalToDecimal(decimalNumb));
}
static int octalToDecimal(int n) 
{ 
        int num = n; 
        int dec_value = 0; 
        int base = 1; 
        int temp = num; 
        while (temp > 0) { 
            int last_digit = temp % 10; 
            temp = temp / 10; 
            dec_value += last_digit * base; 
            base = base * 8; 
        } 
        return dec_value; 
}