如何计算列表中整数的绝对值之和？

Question

I tried to calc the sum of the abs value of nums in a list like this:我试图在这样的列表中计算 nums 的 abs 值的总和：

stage = sum(sum(abs(board))) # board is a list named before

it returned "bad operand type for abs(): 'list'"它返回“abs（）的错误操作数类型：'list'”

so I tried using map like:所以我尝试使用 map 像：

tmp = list(map(abs,board))

however, the error information remains the same.但是，错误信息保持不变。 What can I do?我能做些什么？

The statements using the sum of 'board' are shown as following:使用'board'之和的语句如下所示：

stage = sum(sum(board))
colfull = numpy.zeros((8, 8), dtype=numpy.int64)
colfull[:,numpy.sum(map(abs,board), axis = 0) == 8] = True

Answer 1

You need map (to map the abs ) and sum (to sum the values).您需要map （到 map 的abs ）和sum （对值求和）。 Hence因此

tmp = sum(map(abs, board))

Answer 2

You can do this with a generator expression passed to sum() :您可以使用传递给sum()的生成器表达式来执行此操作：

stage = sum(abs(x) for x in board)

You can read more about generator expressions in the original PEP .您可以在原始PEP中阅读有关生成器表达式的更多信息。