列表理解（从句子中提取单词）

Question

I am trying to use list comprehension in order to extract only words which have characters which is greater then 3. I already made this line of code which count that words.

ListWord = [len(x.strip(',')) for x in 'Michael Jordan is the best basketball player of all time'.split() if len(x.strip(','))>3]

    ListWord
    Out[73]: [7, 6, 4, 10, 6, 4]

But now I need to see that words not only to count е.g["Michael","Jordan","best","basketball","player","time"]. So can anybody help me how to solve this problem?

Answer 1

Replace len(x.strip(',')) with x.strip(',')

ListWord = [x.strip(',') for x in 'Michael Jordan is the best basketball player of all time'.split() if len(x.strip(','))>3]

print(ListWord)

Answer 2

Let's take a look at your query.

[len(x.strip(',')) for x in 'Michael Jordan is the best basketball player of all time'.split() if len(x.strip(','))>3]

If we break this into components, it will be

[TO_RETURN for CURRENT_ITEM in LIST if CONDITION]

So, if you would like to return something different, replace TO_RETURN . In this case, x.strip(',') instead of len(x.strip(',')) .

Answer 3

Why are you using strip? Simpler to just .split() (that returns a list of each item) of the string, and then check the length of each item in that list:

list_word = [x for x in 'Michael Jordan is the best basketball player of all time'.split() if len(x)>3]

Output:

print(list_word)
['Michael', 'Jordan', 'best', 'basketball', 'player', 'time']