如何修复多次输入相同的字符作为猜测？（初学者 Python 项目 - 刽子手游戏）

Question

Inputting the same character multiple times doesn't work. Here is my code for the relevant issue Please be noted that I've unnecessarily complicated my code by working on it for a long time to resolve the problem. I'd really appreciate a correction from anybody. Thanks in advance

def gamefunction():
    global chosenword
    global wordlen
    global attempts

    chosenwordlist = []

    tally = 1
    print("\nThe word to guess is....\n")
    print(chosenword)

    display = "_" * len(chosenword)
    print(display)

    for i in chosenword:
        chosenwordlist.append(i)

    print(chosenwordlist)

    while tally <= int(attempts):
        userchoice = input()
        guessedletters = []
        sameletterguess = []

        if len(userchoice.strip()) == 1:
            occcurence1 = chosenword.find(userchoice)

            if (userchoice in chosenword) and (chosenwordlist.count(userchoice) == 1):
                display = display[:occcurence1] + userchoice + display[occcurence1 + 1:]
                guessedletters.append(userchoice)

            elif (userchoice in chosenword) and (chosenwordlist.count(userchoice) > 1):
                sameletterguess.append(userchoice)
                display = display[:occcurence1] + userchoice + display[occcurence1 + 1:]
                guessedletters.append(userchoice)

                print(sameletterguess)
                print(sameletterguess.count(userchoice))

                if sameletterguess.count(userchoice) == 2:
                    occurence2 = chosenword.find(userchoice,chosenword.find(userchoice)+1)
                    display = display[:occurence2] + userchoice + display[occurence2 + 1:]
                    guessedletters.append(userchoice)
                    print(sameletterguess)

                elif sameletterguess.count(userchoice) == 3:
                    occurence3 = chosenword.find(userchoice, chosenword.find(userchoice,chosenword.find(userchoice)+1)+1)
                    display = display[:occurence3] + userchoice + display[occurence3 + 1:]
                    guessedletters.append(userchoice)
                    print(sameletterguess)

                elif sameletterguess.count(userchoice) == 4:
                    occurence4 = chosenword.find(userchoice, chosenword.find(userchoice, chosenword.find(userchoice,chosenword.find(userchoice)+1)+1)+1)
                    display = display[:occurence4] + userchoice + display[occurence4 + 1:]
                    guessedletters.append(userchoice)
                    print(sameletterguess)

            else:
                print("Wrong guess")
                tally = tally + 1

            print("\n" + display)

            if display == chosenword:
                tally = int(attempts) + 1
                print("Congratulations\nYou guessed the word correctly")

        else:
            print("Invalid input\nEnter only a single letter\n")
            print(display)

For further understanding - It seems like the code doesn't run through the if-else loop nested within the 'if len(userchoice.strip()) == 1:' loop

Answer 1

One possible solution for your problem is as below. Extensive comments inside the code.

#Defining globals. Note: Using globals is bad practice, use function arguments instead
chosenword = 'boot'
attempts = 4

def gamefunction():
    global chosenword
    global attempts
    
    #Create needed extra variables directly from input
    wordlen = len(chosenword)
    chosenwordlist = list(chosenword)

    tally = 1
    print("\nThe word to guess is....\n")
    print(chosenword)
    
    #Added whitespace for better wordlength visualisation
    display = "_ " * wordlen
    print(display)

    print(chosenwordlist)

    #This holds the letters that have been guessed already
    guessedletters = []

    while tally <= int(attempts):
        display = ''
        userchoice = input()

        if len(userchoice.strip()) == 1:
            #check if the guess is part of the word to guess
            if userchoice in chosenwordlist:
                # Check if letter has been guessed before
                if userchoice in guessedletters:
                    print('You tried that letter already')
                    continue
                else:
                    # Add the guessed letter to the list of all guessed letters and create display
                    guessedletters.append(userchoice)
                    for i in range(wordlen):
                        if chosenwordlist[i] in guessedletters:
                            display+=chosenwordlist[i]
                        else:
                            display+='_ '
            else:
                print("Wrong guess")
                tally = tally + 1

            print("\n" + display)

            if display == chosenword:
                tally = int(attempts) + 1
                print("Congratulations\nYou guessed the word correctly")

        else:
            print("Invalid input\nEnter only a single letter\n")
            print(display)