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使用 Python 返回字典列表文本文件中最大字段的行?

[英]Return line of largest field in list of dictionaries text file with Python?

I'm writing a Python script.我正在写一个 Python 脚本。 I need to return line that contain largest 'uid' field from a text file.我需要从文本文件中返回包含最大“uid”字段的行。 For example, in the below text file example:例如,在下面的文本文件示例中:

{
    "uid": 683,
    "user_id": "2",
    "timestamp": datetime.datetime(2020, 5, 17, 16, 39, 54),
    "status": 1,
    "punch": 0,
}, {
    "uid": 684,
    "user_id": "4",
    "timestamp": datetime.datetime(2020, 5, 17, 16, 41, 20),
    "status": 1,
    "punch": 0,
}

Return Text File ex:返回文本文件例如:

{
    "uid": 684,
    "user_id": "4",
    "timestamp": datetime.datetime(2020, 5, 17, 16, 41, 20),
    "status": 1,
    "punch": 0,
}

Here is my solution, instead of reading a text file I used a text from string variable text .这是我的解决方案,我没有读取文本文件,而是使用了来自字符串变量text的文本。

Final result (entry with maximal uid) is contained inside max_entry variable.最终结果(具有最大 uid 的条目)包含在max_entry变量中。 This result I write as string into text file result.txt .我将此结果作为字符串写入文本文件result.txt

Try it online! 在线尝试!

import datetime

text = """
{
    "uid": 683,
    "user_id": "2",
    "timestamp": datetime.datetime(2020, 5, 17, 16, 39, 54),
    "status": 1,
    "punch": 0,
}, {
    "uid": 684,
    "user_id": "4",
    "timestamp": datetime.datetime(2020, 5, 17, 16, 41, 20),
    "status": 1,
    "punch": 0,
}
"""

data = eval('[' + text + ']')
max_entry = max(data, key = lambda e: e['uid'])
print(max_entry)

with open('result.txt', 'w', encoding = 'utf-8') as f:
    f.write(str(max_entry))

Output: Output:

{'uid': 684, 'user_id': '4', 'timestamp': datetime.datetime(2020, 5, 17, 16, 41, 20), 'status': 1, 'punch': 0}

You show that your "text-file" is a list of dictionaries.你表明你的“文本文件”是一个字典列表。 So you could do something like:因此,您可以执行以下操作:

import datetime

text_file = {
    "uid": 683,
    "user_id": "2",
    "timestamp": datetime.datetime(2020, 5, 17, 16, 39, 54),
    "status": 1,
    "punch": 0,
}, {
    "uid": 684,
    "user_id": "4",
    "timestamp": datetime.datetime(2020, 5, 17, 16, 41, 20),
    "status": 1,
    "punch": 0,
}

def return_highest_ui_line(text_file):
    temp = []
    for i,sub_dict in enumerate(text_file):
        temp.append([sub_dict['uid'],i])
    return text_file[sorted(temp)[-1][1]]


return_highest_ui_line(text_file)

output:
{'uid': 684,
 'user_id': '4',
 'timestamp': datetime.datetime(2020, 5, 17, 16, 41, 20),
 'status': 1,
 'punch': 0}

     

I solved this by:我通过以下方式解决了这个问题:

import datetime
with open('C:/Users/UI UX/Desktop/newss.txt') as infile:
    for line in infile:
        data = eval('[' + line + ']')
        max_entry = max(data, key=lambda e: e['uid'])
        print(max_entry)

        with open('result.txt', 'w', encoding='utf-8') as f:
            f.write(str(max_entry))

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