如何在 python 中按字母顺序对字符串进行排序

Question

I've been trying to sort a string in alphabetical order and got stuck. I know that the sort function exists on python but i cant use it. Cant even use the.join method as well. Gotta do it all using for loops.

def wordOrder(word):
    word =  list(word)
    for i in range(0, len(word)):
        for j in range(i, len(word)):
            if word[i] > word[j]:
                word[i], word[j] = word[j], word[i]
    word = ""+ str(word)
    return word

Here's what i have but I did it with a tutor and cant remember what the if section does. Thank you!

Answer 1

You can use ( >, <, <=, <=, ==, .= ) to compare two strings. Python compares string lexicographically ie using ASCII value of the characters.

If statement compares the first and second letter's ASCII value. if its greater than exchange.

for example,

print(wordOrder('ba'))

output
['a', 'b']

ASCII value of small a is 97 and b is 98 .

if word[i] > word[j]:
                word[i], word[j] = word[j], word[i]

So,

 word[i] --> b --> 98
 word[j]  --> a --> 97

Since, 98 is greater than 97 we swap both the values.