根据 python 中的 \n 将列表拆分为 n 个块

Question

I have a list like:

prices=['deposit:2000$ \n monthly:500$','deposit:3500$ \n monthly:800$','deposit:2800$ \n monthly:670$',...]

I want to divide this list into deposit sub list and monthly sub list. I just need to split this according \n (new line). like:

deposit=[deposit:2000$,deposit:3000$,deposit:2800$,....]

monthly=[monthly:500$,monthly:800$,monthly:670$,...]

but I don't know how I can fix it.

Answer 1

You can use list comprehension twice,

prices=['deposit:2000$ \n monthly:500$','deposit:3500$ \n monthly:800$','deposit:2800$ \n monthly:670$']

deposit = [item.split("\n")[0].strip() for item in prices]
monthly = [item.split("\n")[1].strip() for item in prices]

You can also do this in one step using zip,

deposits, monthly = zip(*[item.split("\n ") for item in prices])

Note that the returned deposits and monthly will be tuple. You can cast it to list if needed.

Answer 2

something like the below

prices = ['deposit:2000$ \n monthly:500$', 'deposit:3500$ \n monthly:800$', 'deposit:2800$ \n monthly:670$']
deposit = []
monthly = []
for p in prices:
    d, m = p.split('\n')
    deposit.append(d)
    monthly.append(m)
print(f'{monthly} {deposit}')

output

[' monthly:500$', ' monthly:800$', ' monthly:670$'] ['deposit:2000$ ', 'deposit:3500$ ', 'deposit:2800$ ']