删除备用节点：编译器给我错误的答案 idk 为什么

Question

Given a Singly Linked List of size N, delete all alternate nodes of the list.

Example 1:

Input: LinkedList: 1->2->3->4->5->6
Output: 1->3->5
Explanation: Deleting alternate nodes
results in the linked list with elements 1->3->5.

my code

class Solution {
    
    public void deleteAlternate (Node head){
        //Write your code here
        Node a = head;
        int i = 0;
        
        while(a!= null){
            if(i%2==0){
                System.out.print(a.data+" ");
            }
            i++;
            a = a.next;
            
        }
        
        System.out.println();
    }
}

my output

For Input:
6
1 2 3 4 5 6
your output is:
1 3 5
1 2 3 4 5 6

Answer 1

Your current code is just printing all elements at odd positions in your list. However, you are expected to modify the list. Here is an example of steps which can be performed to remove the element "2" from the list:

• When on element "1", you read the link to the next element which should be deleted (element "2")
• You read the link from the element "2" to the next element "3"
• You save the link to element "3" into the "next" field of the element "1", so now the next element for "1" will be "3".