[英]PHP DomXpath xpath query of Child Node
I'm trying to use xpath to query some HTML:我正在尝试使用 xpath 来查询一些 HTML:
<a target="_blank" class="dx-smart-widget-grid-item_113_20" href="https://link.com" title="Rules for the Road to One Source of Truth' with Jaguar Land Rover and Spark44">
<div class="dx-smart-widget-grid-info_113_20">
<img class="dx-smart-widget-report-cover_113_20" src="https://imagelink.com/preview.png" alt="The Alternative Text"/>
<div class="dx-smart-widget-grid-text_113_20">
<div class="dx-smart-widget-grid-title_113_20">The Alternative Text</div>
</div>
<span class="dx-smart-widget-report-assettype_113_20">On-Demand Webinar</span>
<img class="dx-smart-widget-partner-logo_113_20" src="https://logopath/logo.png" alt="censhare"/>
</div>
</a>
This is the code I'm using:这是我正在使用的代码:
@ $dom->loadHTML($html);
$xpath = new DOMXpath($dom);
$elements = $xpath->query("//a[contains(@class,'dx-smart-widget-grid-item_113_20')]");
if (!is_null($elements)) {
foreach ($elements as $element) {
echo "<strong>Link: </strong>". $element->getAttribute('href'). "<br />";
echo "<strong>Title: </strong>". $element->getAttribute('title'). "<br />";
$images = $xpath->query("//img[contains(@class,'dx-smart-widget-report-cover_113_20')]", $element);
echo "<strong>Image: </strong>".$images->getAttribute('src'). "<br />";
}
}
I'm gettin the href and title fine... but trying to query the image just isn't working.我得到了 href 和 title 很好......但试图查询图像是行不通的。 It actually breaks.它实际上打破了。
Any help would be appreciated.任何帮助,将不胜感激。
You are almost there.你快到了。 You just need to iterate over $images
in a foreach
loop.您只需要在foreach
循环中迭代$images
即可。 So replace所以更换
echo "<strong>Image: </strong>".$images->getAttribute('src'). "<br />";
with和
foreach ($images as $image) {
echo "<strong>Image: </strong>".$image->getAttribute('src'). "<br /and i>";
};
and it should work.它应该可以工作。
Assuming there is only 1 matching image, you can use XPaths evaluate()
and string()
in the XPath expression to extract the value in one go...假设只有 1 个匹配图像,您可以在 XPath 表达式中使用 XPaths evaluate()
和string()
来提取一个 go 中的值...
$images = $xpath->evaluate("string(//img[contains(@class,'dx-smart-widget-report-cover_113_20')]/@src)", $element);
echo "<strong>Image: </strong>".$images. "<br />";
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