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如何将 Fortran 的复杂类型传递给 C#?

[英]How do you pass Fortran's complex type to C#?

Suppose I have the following Fortran code假设我有以下 Fortran 代码

subroutine COMPLEX_PASSING(r, i, c)
    !DEC$ ATTRIBUTES DLLEXPORT::COMPLEX_PASSING

    REAL*8 :: r, i
    COMPLEX*8 :: c

   c = cmplx((r * 2), (i * 2))

return
end

Fortran code was compiled with Fortran 代码编译用

gfortran -c complex_passing.f90
gfortran -fPIC -shared -o complex_passing.dll complex_passing.o

How would I call this subroutine in C#?我如何在 C# 中调用这个子程序? I have tried the following code:我尝试了以下代码:

using System;
using System.Runtime.InteropServices;

namespace FortranCalling {
    class Program {
        static void main(string[] args) {
            double real = 4;
            double imaginary = 10;
            COMPLEX c = new COMPLEX();

            complex_passing( ref real, ref imaginary, ref c);
            Console.WriteLine("Real: {0}\nImaginary: {1}", c.real, c.imaginary);
            Console.ReadLine();
        }

        [StructLayout(LayoutKind.Sequential)]
        struct COMPLEX {
            public double real;
            public double imaginary;
        }

        [DllImport("complex_passing.dll", EntryPoint = "complex_passing_", CallingConvention = CallingConvention.Cdecl)]
        static extern void complex_passing(ref double r, ref double i, ref COMPLEX c);
    }
}
            

With little success - my COMPLEX struct seems to be returning garbage data:收效甚微 - 我的 COMPLEX 结构似乎正在返回垃圾数据:

Real: 134217760.5
Imaginary: 0

When I would expect the real part to be 8 and the imaginary part to be 20.当我期望实部是 8 而虚部是 20 时。

gfortran treats the non-standard COMPLEX*8 as a complex of size 8 bytes, with real and imaginary components 4 bytes each. gfortran 将非标准COMPLEX*8视为大小为 8 字节的复数,实部和虚部各 4 字节。 You instead require a complex of 16 bytes, with real and imaginary components of 8 bytes each ( COMPLEX*16 ) or you should change the C# side accordingly.相反,您需要一个 16 字节的复数,实部和虚部各有 8 个字节( COMPLEX*16 ),或者您应该相应地更改 C# 端。

The effect of this is visible with the following under gfortran:在 gfortran 下可以看到以下效果:

complex*8 :: c8 = (8d0, 20d0)
complex*16 :: c16 = 0

c16%re = TRANSFER(c8,c16)

print*, c8, c16 

end

Of course, you shouldn't be using complex* at all.当然,您根本不应该使用complex* The argument mismatch can be seen using complex(kind=..) .使用complex(kind=..)可以看到参数不匹配。

Consider the following "Fortran" source:考虑以下“Fortran”源:

subroutine s(r, i, c)
  real(kind(0d0)) :: r, i
  complex(kind(0e0)) :: c
  c = cmplx((r*2),(i*2))
end subroutine s

interface ! Interface block required to lie to some versions of gfortran 
subroutine s(r, i, c)
  real(kind(0d0)) :: r, i
  complex(kind(0d0)) :: c
end subroutine s
end interface

complex(kind(0d0)) c
call s(4d0, 10d0, c)
print*, c%re

end

and compare it with the Fortran source:并将其与 Fortran 源进行比较:

subroutine s(r, i, c)
  real(kind(0d0)) :: r, i
  complex(kind(0d0)) :: c
  c = cmplx((r*2),(i*2))
end subroutine s

complex(kind(0d0)) c
call s(4d0, 10d0, c)
print*, c%re

end

Further, rather than using kind(0d0) etc., there are the various C interoperability constants and storage-size constants of iso_fortran_env .此外,除了使用kind(0d0)等之外,还有各种 C 互操作性常量和iso_fortran_env的存储大小常量。

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