简体   繁体   English

使用 std::initializer_list 时出现分段错误<std::string>在构造函数中</std::string>

[英]Segmentation fault when Using std::initializer_list<std::string> in Constructor

Hi i am trying to understand how constructors work and so reading different examples.嗨,我正在尝试了解构造函数的工作原理,并阅读不同的示例。 I have a class constructor that takes an initializer_list but it keeps giving Segmentation fault .我有一个 class 构造函数,它接受一个 initializer_list 但它不断给出Segmentation fault The files that i have are as follows:我拥有的文件如下:

  1. strvec.h字符串
class StrVec {
public:
    StrVec(): elements(nullptr), first_free(nullptr), cap(nullptr) {

    }
    StrVec(const StrVec&);
    StrVec(std::initializer_list<std::string> il);
    StrVec &operator=(const StrVec&);
    ~StrVec();
    void push_back(const std::string&);
    void pop_back();
    void reserve(std::size_t);
    void resize(std::size_t, const std::string& = std::string());
    bool empty() const {
        return begin() == end();
    }
    
    
    std::size_t size() const {
        return first_free - elements;
    }
    std::size_t capacity() const{
        return cap - elements;
    }
    std::string *begin() const {
        return elements;
    }
    std::string *end() const {
        return first_free;
    }

    
private:
    static std::allocator<std::string> alloc;
    void chk_n_alloc() {
        if (size() == capacity()){
            reallocate();
        }
    }
    std::pair<std::string*, std::string*> alloc_n_copy(const std::string*, const std::string*);
    void free();
    void reallocate();

    std::string *elements;
    std::string *first_free;
    std::string *cap;
};
  1. strvec.cpp strvec.cpp
StrVec::StrVec(const StrVec &s){
    auto newdata = alloc_n_copy(s.begin(), s.end());
    elements     = newdata.first;
    first_free   = cap = newdata.second;
}

StrVec::StrVec(std::initializer_list<std::string> il){
    for(const auto &s:il){
        push_back(s);
    }
}
std::pair<std::string*, std::string*> StrVec::alloc_n_copy(const std::string *b, const std::string *e){
    auto data = alloc.allocate(e - b);
    return {data, uninitialized_copy(b, e, data)};
}
void StrVec::push_back(const std::string& s){
    chk_n_alloc();
    alloc.construct(first_free++, s);
}
  1. mainfile.cpp主文件.cpp
int main() {
StrVec sv10 { "il1", "il2", "il3", "il4", "il5" };
return 0;
}

My question is how can i resolve this issue and why am i getting this Segmentation fault and what does it mean so that i can avoid it in the future?我的问题是如何解决这个问题,为什么会出现这个Segmentation fault ,这意味着什么,以便我将来可以避免它?

PS: I know that the error is due to the StrVec(std::initializer_list<std::string> il); PS:我知道错误是由于StrVec(std::initializer_list<std::string> il); constructor since if i remove this and its use in the mainfile.cpp then Segmentation fault goes away.构造函数,因为如果我删除它及其在 mainfile.cpp 中的使用,那么Segmentation fault就会消失。

[Just guessing here since you don't show a proper minimal reproducible example .] [只是在这里猜测,因为您没有显示适当的最小可重现示例。]

You have a set of pointers in your class.您的 class 中有一组指针。

Your StrVec(std::initializer_list<std::string> il) constructor does not initialize these pointers, so push_back will most likely use these uninitialized pointers and you will have undefined behavior and the crash.您的StrVec(std::initializer_list<std::string> il)构造函数不会初始化这些指针,因此push_back很可能会使用这些未初始化的指针,并且您将有未定义的行为和崩溃。

You can easily do the default initialization by delegating it to the default constructor:您可以通过将其委托给默认构造函数轻松地进行默认初始化:

StrVec::StrVec(std::initializer_list<std::string> il)
    : StrVec()  // Delegte default initialization
{
    for(const auto &s:il){
        push_back(s);
    }
}

With that said, the std::initializer_list will have a size, which means you can pre-allocate the exact number of elements needed, and then copy them instead of calling push_back in a loop.话虽如此, std::initializer_list将具有大小,这意味着您可以预先分配所需的确切数量的元素,然后复制它们而不是在循环中调用push_back

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM