嵌套字典中值的百分比

Question

I would like to obtain the percentage of values in a nested dictionary of the form:

{'first': OrderedDict([('Jan', 2), ('Feb', 1)]), 'second': OrderedDict([('Jan', 3), ('Feb', 5)])}

The expected result should be like:

{'first': OrderedDict([('Jan', 40%), ('Feb', 16.6%)]), 'second': OrderedDict([('Jan', 60%), ('Feb', 83.3%)])}

The above result should be obtained as percentage: for the dictionary with key 'first':

Jan : 2/5 *100 = 40%
Feb: 1/6 *100 = 16.6%

For the dictionary with key 'second':

Jan : 3/5 *100 = 60%
Feb: 5/6 *100 = 83.3%

Answer 1

Ordered Dictionary in python follows some of the traits as a normal dictionary you can update the value using.update('k': 'v')

for k, v in d.items(): v.update({'Jan': (v['Jan']/5)*100}) v.update({'Feb': (v['Feb']/6)*100})

Answer 2

The above answer is pretty good, but if you want to get the total values for all months you can try for loop two times, First to sum all values and second to update changes, like:

x={'first': OrderedDict([('Jan', 2), ('Feb', 1)]), 'second': OrderedDict([('Jan', 3), ('Feb', 5)])}

total = [0]*2
for k in x :
    for idx, month in enumerate(x[k]):
        total[idx] += x[k][month]

for k, v in x.items():
    for idx, month in enumerate(v) : 
        v.update({month:round((v[month]/total[idx])*100,2)})

print(x)

This will generate output as:

{'first': OrderedDict([('Jan', 40.0), ('Feb', 16.67)]),
 'second': OrderedDict([('Jan', 60.0), ('Feb', 83.33)])}