[英]Switch-case statement in Python
I'm tired of trying to make a menu that let's me choose from a dictionary keys and in every value I have the choice.我厌倦了尝试制作一个让我从字典键中进行选择的菜单,并且在每个值中我都可以选择。 I found that I can use dictionary and get() method, it's working fine, but I should use if else statement after get() to execute a function that answers the user choice.
我发现我可以使用字典和 get() 方法,它工作正常,但我应该在 get() 之后使用 if else 语句来执行回答用户选择的 function。 Can I do it better?
我可以做得更好吗? Maybe using a lambda inside the key value?
也许在键值内使用 lambda ?
def menu():
print("Welcome to Our Website")
choises={
1:"Login" ,
2:"Register",
}
for i in choises.keys(): # Loop to print all Choises and key of choise !
print(f"{i} - {choises[i]}")
arg=int(input("Pleasse Chose : "))
R=choises.get(arg,-1)
while R==-1:
print("\n Wrong Choise ! Try again ....\n")
menu()
else:
print(f"You Chosed {R}")
if R==1:
login()
if R==2:
register()
def register():
print("Registration Section")
def login():
print("Login Section")
menu()
you can simulate a switch statement using the following function definition:您可以使用以下 function 定义模拟 switch 语句:
def switch(v): yield lambda *c: v in c
You can use it in C-style:您可以在 C 风格中使用它:
x = 3
for case in switch(x):
if case(1):
# do something
break
if case(2,4):
# do some other thing
break
if case(3):
# do something else
break
else:
# deal with other values of x
Or you can use if/elif/else patterns without the breaks:或者您可以使用 if/elif/else 模式而不使用中断:
x = 3
for case in switch(x):
if case(1):
# do something
elif case(2,4):
# do some other thing
elif case(3):
# do something else
else:
# deal with other values of x
It can be particularly expressive for function dispatch它对于 function 调度特别有表现力
functionKey = 'f2'
for case in switch(functionKey):
if case('f1'): return findPerson()
if case('f2'): return editAccount()
if case('f3'): return saveChanges()
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