MySQL 版本 8.0.17 - 仅替换字符串中的第一个空格

Question

In the table stored an a database MySql version 8.0.17 I have this string

Sheriff Curtis Edward

I need replace in this string only the first space for this return

SheriffCurtis Edward

This will make future surname entries work even if the given surname is a double surname...

I have tried this sql but the return is wrong...

SELECT SUBSTRING('Sheriff Curtis Edward',
                 INSTR('Sheriff Curtis Edward', ' ') + 1,
                 CHAR_LENGTH('Sheriff Curtis Edward') - INSTR('Sheriff Curtis Edward', ' ')) new_string;
+---------------+
| new_string    |
+---------------+
| Curtis Edward |
+---------------+
1 row in set (0.10 sec)

Answer 1

You could use REGEXP_REPLACE here with a capture group:

SELECT
    col,
    REGEXP_REPLACE(col, '^(\\S+) ', '$1') AS col_out
FROM yourTable;

Demo

Answer 2

Using your subtring() approach, you could also extract the substring before the space and concatenate it with the substring after the space.

SELECT concat(substring(x.s,
                        1,
                        instr(x.s,
                              ' ')
                        - 1),
              substring(x.s,
                        instr(x.s,
                              ' ')
                        + 1,
                        char_length(x.s)
                        - instr(x.s,
                                ' ')))
       FROM (SELECT 'Sheriff Curtis Edward' s) x