[英]IPv6ToBigInteger
I have this function which uses InetAddress
, but the output is occasionally wrong.我有这个使用
InetAddress
的 function ,但 output 偶尔会出错。 (example: "::ffff:49e7:a9b2"
will give an incorrect result.) (例如:
"::ffff:49e7:a9b2"
将给出不正确的结果。)
def IPv6ToBigInteger(ip: String): BigInteger = {
val i = InetAddress.getByName(ip)
val a: Array[Byte] = i.getAddress
new BigInteger(1, a)
}
And the I also have this function我也有这个 function
def IPv6ToBigInteger(ip: String): BigInteger = {
val fragments = ip.split(":|\\.|::").filter(_.nonEmpty)
require(fragments.length <= 8, "Bad IPv6")
var ipNum = new BigInteger("0")
for (i <-fragments.indices) {
val frag2Long = new BigInteger(s"${fragments(i)}", 16)
ipNum = frag2Long.or(ipNum.shiftLeft(16))
}
ipNum
}
which appears to have a parsing error because it gives the wrong output unless it is in 0:0:0:0:0:0:0:0
format, but is an based on my IPv4ToLong function:这似乎有一个解析错误,因为它给出了错误的 output 除非它是
0:0:0:0:0:0:0:0
格式,但它基于我的 IPv4ToLong function:
def IPv4ToLong(ip: String): Long = {
val fragments = ip.split('.')
var ipNum = 0L
for (i <- fragments.indices) {
val frag2Long = fragments(i).toLong
ipNum = frag2Long | ipNum << 8L
}
ipNum
}
This这个
ipNum = frag2Long | ipNum << 8L
is是
ipNum = (frag2Long | ipNum) << 8L
not不是
ipNum = frag2Long | (ipNum << 8L)
[ And please use foldLeft
rather than var
and while
] [请使用
foldLeft
而不是var
和while
]
Interesting challenge: transform IP address strings into BigInt
values, allowing for all legal IPv6 address forms.有趣的挑战:将 IP 地址字符串转换为
BigInt
值,允许所有合法的 IPv6 地址 forms。
Here's my try.这是我的尝试。
import scala.util.Try
def iPv62BigInt(ip: String): Try[BigInt] = Try{
val fill = ":0:" * (8 - ip.split("[:.]").count(_.nonEmpty))
val fullArr =
raw"((?<=\.)(\d+)|(\d+)(?=\.))".r
.replaceAllIn(ip, _.group(1).toInt.toHexString)
.replace("::", fill)
.split("[:.]")
.collect{case s if s.nonEmpty => s"000$s".takeRight(4)}
if (fullArr.length == 8) BigInt(fullArr.mkString, 16)
else throw new NumberFormatException("wrong number of elements")
}
This is, admittedly, a bit lenient in that it won't catch all all non-IPv6 forms, but that's not a trivial task using tools like regex.诚然,这有点宽松,因为它不会捕获所有非 IPv6 forms,但使用正则表达式之类的工具并不是一件容易的事。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.