重载 'write(int)' 的调用不明确

Question

Right now, i am trying to print a special character to my LCD screen. for some reason- this message appears: call of overloaded 'write(int)' is ambiguous

I have no idea what this means, and help would be great.

Code:

#include <LiquidCrystal.h>

LiquidCrystal lcd(1, 2, 4, 5, 6, 7);

byte customChar[] = {
  B01110,
  B01110,
  B01110,
  B00100,
  B01110,
  B10101,
  B00100,
  B01010
};


void setup() {
  
   lcd.begin(16, 2);
  lcd.createChar(0, customChar);
  lcd.home();
  lcd.write(0);
}

void loop() {
  for(int position = 0; position < 13; position++) {
  lcd.scrollDisplayRight();
  delay(150);

  int state = digitalRead(8);
  if (state != 0) {
    if (state == HIGH) {

    lcd.clear();
    lcd.print("Hello!");
    }
  }
  }
}

Any help?

Answer 1

LiquidCrystal is a subclass of Print which has two write() methods: virtual size_t write(uint8_t); and size_t write(const char *str) . With a parameter of 0 either of those could be called hence it is ambiguous.

Try casting to the type you want: write(static_cast<uint8_t>(0))