在没有任何模块/库的情况下将列表列表写入 csv 文件

Question

I've the following list of lists:

l=[a,b,c,d]

where a,b,c,d are separate lists with different data types in each list.

I'm trying to write each list as a separate column to the CSV file with headers as the name of the list.

for ex:

ab c d 1 a \pt

I've tried the following approach: converted them to a zip

l=zip(a,b,c,d)

and writing to CSV file:

out = open('out.csv', 'w')
for row in l:
  for column in row:
    out.write('%s,' % column)
      out.write('\n')

However, in this case, since one of the lists b has text data, the separator, is not working and for that fact any separator being used in out.write('%s,' % column) results in the wrong output.

Is there a way to solve this problem without using any modules?

Answer 1

This puts quote marks around each item:

for row in i:
  out.write( '"' + '","'.join(row) + '"\n' )

However, the built-in csv module is smarter, easy to use, and comes for free.