分页 laravel 集合返回 404

Question

I have paginated my collection and it shows pagination but when I click on page numbers it return 404 error

Route

Route::post('search', 'front\SearchController@results')->name('search');

Blade (form)

<form action="{{route('search')}}" method="POST">
  @csrf
  @method('POST')
  <input  class="input" type="search" name="q">
</form>

Controller

public function results(Request $request) {
  $q = $request->input('q');
  $rres = array_merge('//my data...');
  $perPage = 12;
  $page = null ?: (Paginator::resolveCurrentPage() ?: 1);
  $items = $rres instanceof Collection ? $rres : Collection::make($rres);
  $rres = new LengthAwarePaginator($items->forPage($page, $perPage), $items->count(), $perPage, $page, [
    'path' => Paginator::resolveCurrentPath()
  ]);
  return view('front.pages.new-search', compact('q', 'rres'))->withQuery($q);
}

Blade (pagination)

{{$rres->links('front.pages.search-paginate')}}
// URL of other pages is like:
// http://example.com/search?page=2
// while url of page 1 is like
// http://example.com/search (refer to route code above)

Any idea?

Answer 1

Links only support GET and HEAD methods, try to add:

Route::get('search', 'front\SearchController@results')->name('search');

Note that you only have to add above, no need to remove your POST -method from routes.

Answer 2

You are missing the return statement in your results method.

return new LengthAwarePaginator($items->forPage($page, $perPage), $items->count(), $perPage, $page, [
    'path' => Paginator::resolveCurrentPath()
]);

Edit: I see you are returning a view after an HTTP POST which is really a bad design choice. You can google about the PRG Pattern and you will find many articles that will explain why you should always redirect to an HTTP GET which will render your view.

Instead, you should use a GET request for this.