导入 main.py 中的所有包

Question

I'd like to import all my packages in only one file.

Let assume that I have a main.py file where I call all my class (from others.py files located in a src folder):

main.py
|-- src
  |-- package1.py
  |-- package2.py

the main.py looks like this:

from src.package1 import *
from src.package2 import *

def main():
    class1 = ClassFromPackage1()
    class2 = ClassFromPackage2()

if __name__ == '__main__':
    main()

in package1.py I import let say numpy, scipy and pandas

import numpy
import scipy
import pandas

class ClassFromPackage1():
    #  Do stuff using numpy, scipy and pandas

and in package2.py I use numpy and scikit learn:

import numpy
import sklearn

class ClassFromPackage2():
    #  Do stuff using numpy and sklearn

Is there a way to import all packages in one file Foo.py where I only write:

import numpy
import sklearn
import scipy
import pandas

and import this Foo.py in src.py? like this for example with package1.py

import Foo

class ClassFromPackage1():
    #  Do stuff using numpy, scipy and pandas

Is this a good idea? Does it reduce memory consumption? Will it helps python to start the main.py faster?

Answer 1

Looks like you want to make code cleaner? What you can do is create a file like foo.py and put all imports in it. Then you can import modules inside foo.py by doing

from foo import *

This will indirectly import all modules.

Answer 2

The way you have already done it is how it is usually done. Similar to header files in C/C++, you make the dependencies explicit. And that it is a good thing.

You asked if it will run faster, the answer is no. All imports are shared. This, sometimes, causes unwanted side effects, but that is not the question here.