一种在文本文档中查找单词并删除带有该单词的行和以下 6 行的方法（Python）

Question

Is there a way to open a text file, find a word, delete the line with the word, and the following 6 lines of it?

Answer 1

This should work

def look_and_delete(file,word_to_look_for):
  files = open(file,'r')
  contents = files.readlines()
  print(contents)
  line  = 0
  file_words = ''
  for i in contents:
    print(i)
    if word_to_look_for in i:
      print("im in here on line", line)
    else:
      file_words+=i
    line+=1
  print(file_words)
  files.close()
  files = open(file,'w')
  files.write(file_words)
  files.close()

Fell free to remove the print statement they are irrelevant

Answer 2

Here I have explain logic for file editing with various section:

First we open file in read write mode because r+ doesn't overwrite the previously written file

f = open("file.txt", 'r')
content = f.read()

---

Then we split it into various line

lines_ = content.split('\n')[::-1]
word = input('Enter your words : ')

---

Apply logic to remove maatch word line and 6 consecutive line.

for i, j in zip(range(len(lines_)), lines_):
    if word in j:
        for k in range(7):
            if i > abs(k):
                del lines_[i-k]
file_ = '\n'.join(lines_[::-1])
f.close()

---

Again we open file to write that updated string into file back that is why we use w write mode which first clear the file then place string into it

with open("file.txt", 'w') as f:
    f.write(file_)

Answer 3

I would approach it in another way
First open file and read lines for later, n=5 means - remove 5 lines including line with magic word.

magic_word = 'foo'
n = 5
with open('file.txt', 'r') as file_handle:
    lines = file_handle.readlines()
num_lines = len(lines)

Next we enumerate over lines but in reverse. This is very important for a corner case, ex.:
If we take this kind of input:

test1
foo
test2
test3
test4
foo
test5
test6
test7
test8

Reading file from start to end (let n=5 ) and looking for a magic word will result with output:

test1
test5
test6
test7
test8

But if we look and remove from the other end the result is:

test1

That is why we need to revere the order.

strip is just so we can remove \n before comparison.

for idx, word in enumerate(reversed(lines)):
    # now going from the end of a file
    word = word.strip()

When we find magic word, we have to remove n line from this point to file end. Easiest operation to remove parts of a iterable in python is to slice

ex. obj[1:5] cut objects in range <1,5> or obj[:5] cut objects in range <0,5>

    if word == magic_word:
        left_bound = num_lines-idx-1
        if left_bound + n >= num_lines:
            lines = lines[:left_bound]
        else:
            lines = lines[:left_bound] + lines[left_bound+n:]

All that is left is to save the file(override)

with open('file.txt', 'w') as file_handle:
    lines = file_handle.writelines(lines)