[英]Split vector of class into vector of class member
I found a problem in C++ that I cannot solve by myself and so I would like to ask you, if there is a possibility to split vector of class into vector of class member .我在 C++ 中发现了一个我自己无法解决的问题,所以我想问你,是否有可能将class的向量拆分为class 成员的向量。
class CPerson
{
public:
string m_Name;
string m_Surname;
}
class CPersonList
{
public:
CPersonList ( const vector<CPerson> & ref )
{
m_List = ref;
}
private:
vector<CPerson> m_List;
}
class CAllPersonsData
{
public:
CPersonList "MYPROBLEM" ( ) { CPersonList listAlfa ("IDONOTKNOW"); return listAlfa; }
private:
class CData
{
public:
CPerson m_Person;
string m_Data;
}
vector<CData> m_Alldata;
"MYPROBLEM" is a method which should create and return CPersonList listAlfa. “MYPROBLEM”是一个应该创建并返回 CPersonList listAlfa 的方法。
listAlfa should be created by constructor, where I would like to pass vector created from vector . listAlfa应该由构造函数创建,我想传递从vector创建的向量。 In my eyes, "IDONOTKNOW" should look like vector<CData.CPerson> .
在我看来,“IDONOTKNOW”应该看起来像vector<CData.CPerson> 。 So, there should be same data as in vector but without atributes m_Data .
因此,应该有与向量中相同的数据,但没有属性m_Data 。
Is there any option how to do this?有什么选择如何做到这一点?
Of course I do not want to copy it, because I would like to pass it just by reference.当然我不想复制它,因为我想通过引用传递它。
Thank you so much for your tips;-)非常感谢您的提示;-)
A vector owns its content so if you want to return a std::vector<CPerson>
you would have to copy the data, for example向量拥有它的内容,所以如果你想返回一个
std::vector<CPerson>
你必须复制数据,例如
std::vector<CPerson> people;
people.reserve(m_Alldata.size());
std::transform(m_Alldata.begin(), m_Alldata.end(), std::back_inserter(people),
[](CData const & data) { return data.m_person; });
return people;
If you want to return a vector of "references" to the instances in m_Alldata
, you could return a std::vector<CPerson *>
:如果要返回
m_Alldata
中实例的“引用”向量,可以返回std::vector<CPerson *>
:
std::vector<CPerson *> people;
people.reserve(m_Alldata.size());
std::transform(m_Alldata.begin(), m_Alldata.end(), std::back_inserter(people),
[](CData const & data) { return &data.m_person; });
return people;
or a std::vector<std::reference_wrapper<CPerson>>
:或
std::vector<std::reference_wrapper<CPerson>>
:
std::vector<std::refernce_wrapper<CPerson>> people;
people.reserve(m_Alldata.size());
std::transform(m_Alldata.begin(), m_Alldata.end(), std::back_inserter(people),
[](CData const & data) { return std::ref(data.m_person); });
return people;
As an alternative to a std::vector
you could return a begin/end pair of iterators that dereference to a CPerson
-reference:作为
std::vector
的替代方案,您可以返回一对取消引用CPerson
引用的开始/结束迭代器:
#include <boost/compute/iterator/transform_iterator.hpp>
using boost::compute::make_transform_iterator;
auto people_begin()
{
return make_transform_iterator(m_Alldata.begin(), [](CData const & data) { return data.m_person; });
}
auto people_end()
{
return make_transform_iterator(m_Alldata.end(), [](CData const & data) { return data.m_person; });
}
If you can use the ranges-library you could return a transform_view of your data:如果您可以使用范围库,则可以返回数据的 transform_view:
#include <ranges>
auto people()
{
return std::ranges::transform_view(m_Alldata, [](CData & data) { return data.m_person; });
}
The returned object has a begin()
and end()
and its iterators dereference to a CPerson &
.返回的 object 具有
begin()
和end()
及其迭代器对CPerson &
的取消引用。
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