正则表达式：如果在 x 范围内以 char 开头，则不匹配

Question

I am trying to use Regex (c#) to do the following:

• Only match if search string '70' is not preceded by ID=" (case insensitive)
• And only match if string before search string '70' does not contain '+'

Example Text (linebreaks only for visuals):

ID="70" Testtext
MultilingualText Uid="70"
Test="+#12-A170"
CV_70

i got the first condition via

(?i)(?<!ID=\")70

which will only match 70 in line 3 & 4 but i have no idea how to exclude the line containing the '+' . The position of '+' is variable in front of the search string.

Answer 1

You might use

(?i)(?<!\+.*)(?<!ID=")70

The pattern matches

• (?i) Modifier for case insensitive
• (?<.\+.*) If a + is not on the left
• (?<!ID=") If ID+ is not directly to the left of the current position
• 70 Match 70

.NET Regex demo

string pattern = @"(?i)(?<!\+.*)(?<!ID="")70";
string input = @"ID=""70"" Testtext
    MultilingualText Uid=""70""
    Test=""+#12-A170""
    CV_70";

foreach (Match m in Regex.Matches(input, pattern))
{
    Console.WriteLine(m.Value);
}

Output

70

Update

The final working pattern as commented by @ anubhava matching any char except double quotes

(?i)(?<!\+[^"]*)(?<!ID=")70

.NET regex demo