[英]How to show Many-to-Many Field on Django Admin Panel?
I have 2 models, Product and Tag.我有 2 个模型,产品和标签。 The relation between product and tag is Many-to-Many Relationship.
产品和标签之间的关系是多对多关系。
How to show "tags" field on django admin panel?如何在 django 管理面板上显示“标签”字段? Currently the value is None when I am using the code below
当我使用下面的代码时,当前值为 None
models.py模型.py
class Tag(models.Model):
name = models.CharField(max_length=200, null=True)
def __str__(self):
return self.name
class Product(models.Model):
CATEGORY = (
('Indoor','Indoor'),
('Outdoor','Outdoor'),
)
name = models.CharField(max_length=200, null=True)
price = models.FloatField(null=True)
category = models.CharField(max_length=200, choices=CATEGORY)
description = models.CharField(max_length=200, null=True)
date_created = models.DateTimeField(auto_now_add=True, null=True)
tags = models.ManyToManyField(Tag)
admin.py管理员.py
@admin.register(Product)
class ProductAdmin(admin.ModelAdmin):
list_display = ['id','name','price','category','tags']
list_display_links = ['name']
def tags(self):
return self.tags.name
try this尝试这个
@admin.register(Product)
class ProductAdmin(admin.ModelAdmin):
list_display = ['id', 'name', 'price', 'category', 'get_tags']
list_display_links = ['name']
def get_tags(self, obj):
if obj.tags.all():
return list(obj.tags.all().values_list('name', flat=True))
else:
return 'NA'
Refer this https://docs.djangoproject.com/en/3.1/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_display请参阅此https://docs.djangoproject.com/en/3.1/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_display
@admin.register(Product)
class ProductAdmin(admin.ModelAdmin):
list_display = ['id','name','price','category','get_tags']
list_display_links = ['name']
def get_tags(self, instance):
return [tag.name for tag in instance.tags.all()]
In Django 4.1 you don't need to pass the second param (instance of class), and can do smth like this:在 Django 4.1 你不需要传递第二个参数(类的实例),并且可以这样做:
@admin.register(Product)
class ProductAdmin(admin.ModelAdmin):
list_display = ['id','name','price','category','get_tags']
list_display_links = ['name']
def get_tags(self):
return [tag.name for tag in instance.tags.all()]
Also, you can detalize this field, and add decorator @admin.display
example for add title for django admin.另外,您可以对该字段进行细化,并添加装饰器
@admin.display
示例,为 django admin 添加标题。 More details in docs: https://docs.djangoproject.com/en/4.1/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_display文档中的更多详细信息: https://docs.djangoproject.com/en/4.1/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_display
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