初学者：Python--如何将 elif 语句嵌入到 while 循环中（每次通过循环都会改变 output 的路线？！）

Question

##Here's an example of what I've been working on: ##so far I've used num set to zero and num set to the full num=int(input statement... I've learned both ways so far and I'm not sure if I need to use it at all, but when I do it's usually for when I have a for statement asking to keep track of for x in range (0, inp+1): which I've already tried to no avail...

##okay, so here's what I've been trying to do for THREE days now... and it will drive me crazy till I get this; I'm trying to get the program to give output while true (that num is not equal to 11, if not equal to 11; print "nope", if nope isn't printed, it's supposed to go on to the next statement. etc,. etc,. until it hits 11. But here's the thing, It's SUPPOSED to try the first statement while true: and change each time through the loop! I have a bunch of other ways I've tried this while racking my brain over it and haven't gotten it QUITE right yet so here's the basic nitty-gritty:

num=0

while num != 11:
    num=int(input("Please enter a number from 1 to 20 (17 to stop): "))
    print(num)
    if num != 11:
        print("nope")
    elif num >=3:
        print("history")
    elif num < 20:
        print("bye")
    elif num > 12:
        print("cat")
    elif num >= 7:
        print("push")
    else:
        print("sat")```

Answer 1

The reason it's not working is because any number that isn't 11 will be caught in the if, then the loop starts again. If you type 11 the loop just prints history then exits. Doing this will first check if it's not 11, then check the other conditions. It's a bit unclear what you want to happen. And 11 is stopping not 17. But hopefully this helps a bit.

num=0
while num != 11:
    num=int(input("Please enter a number from 1 to 20 (17 to stop): "))
    print(num)
    if num != 11:
        print("nope")
    if num >=3:
        print("history")
    elif num < 20:
        print("bye")
    elif num > 12:
        print("cat")
    elif num >= 7:
        print("push")
    else:
        print("sat")

Answer 2

if I enter 8, it's supposed to tell me "nope"; next if I enter 19, it's supposed to just show me the printed input "19"; then if I want to enter 11, it's supposed to just put "11" as the output rather than any of the words. Once it's finished with the loop it starts all over again; in the second round it's like entering "3" and I'm somehow supposed to get "nope"

It sounds like you just want something like:

while True:
    num = int(input("Please enter a number from 1 to 20 (17 to stop): "))
    print(num)
    if num == 11:
        continue
    print("nope")
    while num != 11:
        num = int(input("Please enter a number from 1 to 20 (17 to stop): "))
        print(num)

From your description it doesn't sound like you're ever supposed to see any of the other words so all of that code is unnecessary.