打印关于相似项目的两个相邻的 python 列表

Question

I'm currently playing around with python to deal with duplicate music files. For that I'm looking for a more pythonic way to print 2 lists (length could be unequal) next to each other. It is import though, that the items, which have a similar name are in the same row and it would be great, if it wouldn't matter which lists contains more items. The Formatting could also be a bit better.

This is what I came up with so far:

a = ['01-06 How Does It Feel.mp3', '01-08 Never Walk Away.mp3']

b = ['01 Show Me a Sign.mp3',
 "02 Don't Let Go.mp3",
 '03 All Messed Up.mp3',
 '04 Promise Keeper.mp3',
 '05 Goodbye to You.mp3',
 '06 How Does It Feel.mp3',
 '07 Had Enough of You.mp3',
 '08 Never Walk Away.mp3',
 '09 Nothing Left at All.mp3',
 '10 Reality Show.mp3',
 '11 Killing With Kindness.mp3']


def checkTitleName(org, song):
    for i in org:
        if song in i:
            return i
        
    return None
    

def listViewCompare(org, dub):
    out = ""
    for i in dub:
        match = checkTitleName(org, i)
        if  match == None:
            line = [i, "\t\t --> \t"]
            print(out.join(line))

        else:
            line = [i, "\t\t --> \t", match]
            print(out.join(line))

                
print(listViewCompare(a,b))

Output:

01 Show Me a Sign.mp3        -->    
02 Don't Let Go.mp3      -->    
03 All Messed Up.mp3         -->    
04 Promise Keeper.mp3        -->    
05 Goodbye to You.mp3        -->    
06 How Does It Feel.mp3      -->    01-06 How Does It Feel.mp3
07 Had Enough of You.mp3         -->    
08 Never Walk Away.mp3       -->    01-08 Never Walk Away.mp3
09 Nothing Left at All.mp3       -->    
10 Reality Show.mp3      -->    
11 Killing With Kindness.mp3         -->    
None

Answer 1

You can try this:

a = ['01-06 How Does It Feel.mp3', '01-08 Never Walk Away.mp3']

b = [
    '01 Show Me a Sign.mp3',
     "02 Don't Let Go.mp3",
     '03 All Messed Up.mp3',
     '04 Promise Keeper.mp3',
     '05 Goodbye to You.mp3',
     '06 How Does It Feel.mp3',
     '07 Had Enough of You.mp3',
     '08 Never Walk Away.mp3',
     '09 Nothing Left at All.mp3',
     '10 Reality Show.mp3',
     '11 Killing With Kindness.mp3',
]


length = max(len(s) for s in b)

for i in b:
    for j in a:
        if i in j[3:]:
            print(f"{i:{length}} -> {j}")
    print(f"{i:{length}} ->")

Output:

01 Show Me a Sign.mp3        ->
02 Don't Let Go.mp3          ->
03 All Messed Up.mp3         ->
04 Promise Keeper.mp3        ->
05 Goodbye to You.mp3        ->
06 How Does It Feel.mp3      -> 01-06 How Does It Feel.mp3
06 How Does It Feel.mp3      ->
07 Had Enough of You.mp3     ->
08 Never Walk Away.mp3       -> 01-08 Never Walk Away.mp3
08 Never Walk Away.mp3       ->
09 Nothing Left at All.mp3   ->
10 Reality Show.mp3          ->
11 Killing With Kindness.mp3 ->