[英]Taking file input from OpenFileDialog
I looked around for an answer to this and couldn't find anything.我环顾四周寻找答案,但找不到任何东西。 All I need to do is take an input from a text file with multiple lines selected from an OpenFileDialog box.我需要做的就是从一个文本文件中获取一个输入,该文件从 OpenFileDialog 框中选择了多行。 Here's a selection from my code:这是我的代码中的一个选择:
if (theDialog.ShowDialog() == DialogResult.OK)
{
try
{
if ((myStream = theDialog.OpenFile()) != null)
{
using (myStream)
{
//I need this to take input given from OpenFileDialog
this.read_display.Text = input;
}
}
}
I'm probably just overlooking something really obvious, but I'm not sure.我可能只是忽略了一些非常明显的东西,但我不确定。
If you want to get the text from stream
, you can create a StreamReader
instance and call method ReadToEnd()
.如果要从stream
获取文本,可以创建StreamReader
实例并调用方法ReadToEnd()
。
string input;
using (StreamReader sr = new StreamReader(myStream))
{
input = sr.ReadToEnd());
}
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