Python：将参数传递给 class 中的方法

Question

So for instance I have a class called Employee and I have a class method designed to raise the wage of an an Employee. I just have issues actually getting my desired raise for the wage passed into the class method as an argument, it's baffling me.

Class module;

Class Employee:
    def __init__(self, name, salary, age):

        self.name = name.title()
        self.salary = salary
        self.age = age

    def raise_wage(self, raise):
        self.salary = self.salary + raise

main module;

def main():
    e1 = Employee("John Smith", 50000, 42)
    Employee.e1.raise_wage(500)

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Passing that 500 in as an arguement is the issue, i get missing positional argument errors for the method etc. How do I pass the argument to the class method?

Hope this makes sense.

Answer 1

1. You can't use raise . It is a reserved word.

2. Use class instead of Class to define a class.

3. Write e1.raise_wage() instead of Employee.e1.raise_wage() .

class Employee:
    def __init__(self, name, salary, age):
        self.name = name.title()
        self.salary = salary
        self.age = age

    def raise_wage(self, amount):
        self.salary = self.salary + amount

e1 = Employee("John Smith", 50000, 42)
e1.raise_wage(500)

print(e1.salary) # output: 50500

Answer 2

raise is a reserved keyword used to raise an exception, change it to other name and it will work just fine. https://www.w3schools.com/python/ref_keyword_raise.asp

Answer 3

raise is a reserved keyword in python for raising exception. use another name for that argument then it will work. And you already created object for Employee so no need to call function with class name again.