[英]Python extract paragraph in text file using regex
I am using Python 3.7 and I am trying to extract some paragraph from some text files using regex.我正在使用 Python 3.7,我正在尝试使用正则表达式从一些文本文件中提取一些段落。
Here is a sample of the txt file content.这是txt文件内容的示例。
AREA: OMBEYI MARKET, ST. RITA RAMULA
DATE: Thursday 25.03.2021, TIME: 9.00 A.M. = 5.00 P.M.
Ombeyi Mk, Kiliti Mkt, Masogo Mkt, Miwani, Kasongo, Onyango Midika, St. Rita Ramula, Onyalo
Biro, Yawo Pri, Obino, Rutek, Keyo Pri & adjacent customers.
AREA: NYAMACHE FACTORY
DATE: Thursday 25.03.2021, TIME: 830 A.M. - 3.00 P.M.
Nyamache Fact, Suguta, Gionseri, Igare, Kionduso, Nyationgongo, Enchoro, Kebuko, Emenwa, Maji
Mazuri, Borangi & adjacent customers.
AREA: SUNEKA MARKET, RIANA MARKET
DATE: Thursday 25.03.2021, TIME: 8.00 A.M. - 3.00 P.M.
Suneka Mk, Riana Mk, Kiabusura, Gesonso, Chisaro, Sugunana, Nyamira Ndogo & adjacent
customers.
AREA: ITIATI, GITUNDUTI
DATE: Thursday 25.03.2021, TIME: 9.00 A.M. = 2.00 P.M.
General China, Gachuiro, Gathuini Pri, Itiati Campus, Kianjugum, Gikore, Kihuri TBC, Gitunduti &
adjacent customers.
Currently I am able to extract the Area, Date and Time using regex:目前我可以使用正则表达式提取区域、日期和时间:
area_pattern = re.compile("^AREA:((.*))")
date_pattern = re.compile("^DATE:(.*),")
time_pattern = re.compile("TIME:(.*).")
I would like to be able to extract the paragraph after DATE/TIME and before AREA containing locations separated by commas.我希望能够在DATE/TIME之后和AREA之前提取包含以逗号分隔的位置的段落。 So I will be able to match the following:所以我将能够匹配以下内容:
1.
Ombeyi Mk, Kiliti Mkt, Masogo Mkt, Miwani, Kasongo, Onyango Midika, St. Rita Ramula, Onyalo
Biro, Yawo Pri, Obino, Rutek, Keyo Pri & adjacent customers.
2.
Nyamache Fact, Suguta, Gionseri, Igare, Kionduso, Nyationgongo, Enchoro, Kebuko, Emenwa, Maji
Mazuri, Borangi & adjacent customers.
3.
Suneka Mk, Riana Mk, Kiabusura, Gesonso, Chisaro, Sugunana, Nyamira Ndogo & adjacent
customers.
4.
General China, Gachuiro, Gathuini Pri, Itiati Campus, Kianjugum, Gikore, Kihuri TBC, Gitunduti &
adjacent customers.
If anyone could help with suggesting a regex that would help with this use case, as well as improvements to my current regex, I would really appreciate it.如果有人可以帮助建议一个对这个用例有帮助的正则表达式,以及对我当前的正则表达式的改进,我将非常感激。 Thanks谢谢
You may use this regex with a capture group to be used in re.findall
:您可以将此正则表达式与要在re.findall
中使用的捕获组一起使用:
\nDATE:.*\n*((?:\n.*)+?)(?=\nAREA:|\Z)
RegEx Details:正则表达式详细信息:
\nDATE:
: Match text DATE:
after matching a line break \nDATE:
: 匹配文本DATE:
匹配换行符后.*\n*
: Match rest of the line followed by 0 or more line breaks .*\n*
: 匹配 rest 后跟 0 个或多个换行符的行((?:\n.*)+?)
: Capture group 1 to capture our text which 1 or lines of everything until next condition is satisfied ((?:\n.*)+?)
:捕获组 1 以捕获我们的文本,其中 1 或所有内容的行,直到满足下一个条件(?=\nAREA:|\Z)
: Assert that we have a line break followed by AREA:
or end of input right ahead of the current position (?=\nAREA:|\Z)
:断言我们有一个换行符,然后是AREA:
或当前 position 之前的输入结束As an alternative pattern:作为替代模式:
^DATE:.*((?:\n(?!AREA:).*)+)
^DATE:.*
Match DATE:
and the rest of the line ^DATE:.*
匹配DATE:
和该行的 rest(
Capture group 1 (
捕获组 1
(?:\n(?:AREA.).*)+
Repeat 1+ lines that do not start with AREA:
(?:\n(?:AREA.).*)+
重复 1+ 行不以AREA:
)
Close group 1 )
关闭第 1 组
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