嵌套的 Python for 循环仅适用于列表中的最后一项

Question

I have encountered an issue where the 2nd for loop in a nested loop in Python only works for the last item in the list.

input = input("Words: ")
print(input)
list = input.split('[:,\s]')
print(list)

for each in list:
    for i, item in enumerate(list):
        joined = each + "TEST"
        print(joined)

As you can see in the code I am trying to loop through every item in the list and then in each loop of the loop before I want to append the string "TEST" to the end of the word that's currently looped through first loop.

Let's parse an input for example "aword, anotherword, yetanotherword, certainword" . I would expect the program to produce the following output "awordTEST, anotherwordTEST, yetanotherwordTEST, certainwordTEST" .

Instead this is the actual output "aword, anotherword, yetanotherword, certainwordTEST" .

I can't figure out why does the 2nd loop only work for the last item in the list.

Edit: suggested solution was to use a single for loop. The thing is that I need to work with that 2nd for loop later and it is important for it to be in that 2nd for loop. Thanks.

Answer 1

str.split does not accept regular expressions to split on. If you look at the contents of list , you'll see it's just the original string. If you want to split on a regex, you must use the re module :

import re

inp = input("Words: ")
print(inp)
lst = re.split(r'[:,\s]+', inp)
print(lst)

for each in lst:
    joined = each + "TEST"
    print(joined)

Try it online!

I removed the inner loop because it was doing nothing but multiplying outputs, and renamed variables to avoid name-shadowing built-ins.

Answer 2

you need change this section:

for each in list:
    for i, item in enumerate(list):
        joined = each + "TEST"
    print(joined)

so the result is

awordTEST
anotherwordTEST
yetanotherwordTEST
certainwordTEST