[英]How to index a Matplotlib subplot
Im trying to plot two piecharts together.我正在尝试将 plot 两个饼图放在一起。 I have been reading the Matplotlib documentation https://matplotlib.org/stable/gallery/pie_and_polar_charts/pie_demo2.htmland cannot see what im doing wrong.
我一直在阅读 Matplotlib 文档https://matplotlib.org/stable/gallery/pie_and_polar_charts/pie_demo2.html并且看不出我做错了什么。 I'm getting an indexing error in line 13 (patches = axs[1,1].pie...)
我在第 13 行遇到索引错误 (patches = axs[1,1].pie...)
The code worked until I started using the axs[1,1] etc and tried to have the subplots.在我开始使用 axs[1,1] 等并尝试使用子图之前,代码一直有效。
Code代码
import matplotlib.pyplot as plt
from matplotlib import rcParams
print('\n'*10)
# Make figure and axes
fig, axs = plt.subplots(1,2)
# Pie chart, where the slices will be ordered and plotted counter-clockwise:
labels = 'Alpha', 'Beta', 'Gamma', 'Phi', 'Theta'
sizes = [3, 6, 2, 3, 10]
explode = (0, 0.1, 0, 0, 0) # only "explode" the 2nd slice (i.e. 'Hogs')
patches = axs[1,1].pie(sizes, explode=explode, labels=labels, autopct='%1.1f%%',
shadow=True, startangle=90)[0]
#patches[2].set_hatch('\\\\') # Pie slice #0 hatched.
axs[1,1].axis('equal') # Equal aspect ratio ensures that pie is drawn as a circle.
plt.title("My title", fontsize=14, fontweight='bold', size=16, y=1.02)
# Pie chart 2
labels = 'Alpha', 'Beta', 'Gamma', 'Phi', 'Theta'
sizes = [3, 6, 2, 3, 10]
explode = (0, 0.1, 0, 0, 0) # only "explode" the 2nd slice (i.e. 'Hogs')
patches = axs[1,2].pie(sizes, explode=explode, labels=labels, autopct='%1.1f%%',
shadow=True, startangle=90)[0]
patches[2].set_hatch('\\\\') # Pie slice #0 hatched.
axs[1,2].axis('equal') # Equal aspect ratio ensures that pie is drawn as a circle.
plt.title("My title", fontsize=14, fontweight='bold', size=16, y=1.02)
plt.show()
Traceback追溯
Traceback (most recent call last):
File "/Users/.../Desktop/WORK/time_1.py", line 13, in <module>
patches = axs[1,1].pie(sizes, explode=explode, labels=labels, autopct='%1.1f%%',
IndexError: too many indices for array: array is 1-dimensional, but 2 were indexed
Array axs
is 1-dimensional, change axs[1,1]
and axs[1,2]
to axs[0]
and axs[1]
, then your code will work.数组
axs
是一维的,将axs[1,1]
和axs[1,2]
更改为axs[0]
和axs[1]
,然后您的代码将起作用。
From matplotlib documentation .来自 matplotlib 文档。
# using the variable ax for single a Axes
fig, ax = plt.subplots()
# using the variable axs for multiple Axes
fig, axs = plt.subplots(2, 2)
# using tuple unpacking for multiple Axes
fig, (ax1, ax2) = plt.subplots(1, 2)
fig, ((ax1, ax2), (ax3, ax4)) = plt.subplots(2, 2)
So your axs
is just a numpy array of shape (2,).所以你的斧头只是一个形状为 (2,) 的
axs
数组。
changing the index should do the trick.更改索引应该可以解决问题。
Change axs[1,1] --> axs[0]
, axs[1,2]--> axs[1]
更改
axs[1,1] --> axs[0]
, axs[1,2]--> axs[1]
The problem is that Matplotlib squeezes the axs
array into a 1D shape if there is only one row or only one column of subplots.问题是如果只有一行或只有一列子图,Matplotlib 会将
axs
数组压缩成一维形状。 Fortunately, this inconsistent bahaviour can be disabled by passing the squeeze
argument:幸运的是,可以通过传递
squeeze
参数来禁用这种不一致的行为:
fig, axs = plt.subplots(1, 2, squeeze=False)
And then you can just normally index into it with axs[0,0]
and axs[0,1]
, like you would if there were multiple rows of subplots.然后您通常可以使用
axs[0,0]
和axs[0,1]
对其进行索引,就像有多行子图一样。
I would recommend to always pass squeeze=False
, so that the behaviour is the same regardless of how many rows there are and automated plotting scripts don't need to come up with special cases for single-row plots (or else risk cryptic errors if somebody later on wants to generate a plot that happens to have only a single row).我建议始终传递
squeeze=False
,这样无论有多少行,行为都是相同的,并且自动绘图脚本不需要为单行图提出特殊情况(否则可能会出现神秘错误,如果后来有人想生成一个 plot,它恰好只有一行)。
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