SQL 根据其他列中的值计算

Question

could use some help with an SQL query...I have a table containing a number of columns. See below sample:

Organisation | Resoure1 | Resource2 | Type
A            |        1 |         4 | W
B            |        4 |         5 | L
C            |        4 |         6 | W
D            |        5 |         3 | W
E            |        4 |         2 | L
A            |        4 |         4 | L
C            |        3 |         5 | L

I have a query that reads from this table and inputs data in another table:

INSERT INTO daily_totals 
(Organisation, Resource1, Resource2, Type) 
SELECT Organisation
     , sum(Resource1)
     , sum(Resource2)
     , SUM(CASE WHEN Type LIKE "W%" THEN 1 ELSE 0 END) 
  FROM db.mytable 
 GROUP 
    BY organisation;

However, I now need a small modification to the above part SUM(CASE WHEN Type LIKE "W%" THEN 1 ELSE 0 END) - column TYPE in total needs to be dependent on Resource1 - Odd numbers in Resource1 need to be rounded to nearest Even number and then halved. Therefore I need to do something like:

SUM(CASE WHEN Type LIKE "W%" THEN 1 ELSE 0 END) * CEILING(sum(CASE WHEN Resource1 = 1 THEN 2 ELSE Resource1 END) / 2 WHERE Type LIKE "W%")

But this results in syntax errors and I cannot figure out a way round it.

Can I get some help with the syntax?

Desired Output in table "Totals":

Organisation | Resource1 | Resource2 | Type
A | 5 | 8 | 2
B | 4 | 5 | 0
C | 7 | 11 | 2
D | 5 | 3 | 3
E | 4 | 2 | 0

Answer 1

If I understand you correctly, what you want is this:

SUM(CASE WHEN Type LIKE 'W%' 
    THEN IF(Resource1 % 2 = 1, Resource1 + 1, Resource1) 
    ELSE 0
    END) / 2