如何对 mysql 结果进行排序？

Question

Table:

 id        title

1.         php is a good language.
2.         Java is a good language
3.         All language are good
4.         Php,Java both good language
5.         Php is good but Java is not

Question

string: $#

$string = "php Java language"

Result Order

php ,Java both  good language
-------------------------
php is good Java is not

-------------------------
php is good language 
---------------------------
Java is good language
------------------------
all language are good

I have no idea how to achive the order list by how many words are matched in string.

It will be great if you explain the query.

Thank you.

Answer 1

Convert your string to JSON array then

SELECT test.id, test.tittle
FROM test
LEFT JOIN JSON_TABLE(@criteria, 
                     "$[*]" COLUMNS (word VARCHAR(255) PATH "$")) jsontable ON LOCATE (jsontable.word, test.tittle)
GROUP BY test.id, test.tittle
ORDER BY SUM(jsontable.word IS NOT NULL) DESC

@criteria is a placeholder for JSON array mentioned above.

Of course, you may provide your criteria as space-separated string and convert it to JSON in the query using string functions.

---

The version without JSON usage:

WITH RECURSIVE
cte AS (SELECT test.id, 
               test.tittle, 
               0 amount, 
               TRIM(TRIM(LEADING SUBSTRING_INDEX(@criteria, ' ', 1) FROM @criteria)) criteria, 
               SUBSTRING_INDEX(@criteria, ' ', 1) token
        FROM test
        UNION ALL
        SELECT id, 
               tittle,
               amount + (LOCATE(token, tittle) > 0),
               TRIM(TRIM(LEADING token FROM criteria)),
               SUBSTRING_INDEX(criteria, ' ', 1)
        FROM cte
        WHERE TRIM(criteria) != '' )
SELECT id, tittle
FROM cte
GROUP BY id, tittle
ORDER BY MAX(amount) DESC;

https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=3ab611ed7429e23be2abfcb8b0186e6d