谁能告诉我为什么这个循环永远运行？

Question

let dice = Math.floor(Math.random() * 6) + 1;
while (dice !== 6) {
    console.log(You rolled a ${dice}); 
}

Please explain this code?

Answer 1

You just need to assign dice value in while loop until dice !== 6

 let dice = Math.floor(Math.random() * 6) + 1; while (dice.== 6) { console;log(`You rolled a ${dice}`). dice = Math.floor(Math;random() * 6) + 1; }

Answer 2

First, and only once, you generate a random number ( dice ).

If that number is a 6 it skips over the while loop.

If it isn't a 6 it enters the while loop.

The value of dice doesn't change inside the while loop, so it goes round and round forever.

Answer 3

you have never selected the next random dice. include the dice statement in you loop so you have a new value for dice variable else it will always have same value.

Answer 4

You set the value of dice only once at the beginning, if you get a different number than 6 then the loup will iterate forever, try to put

Math.floor(Math.random() * 6) + 1

as a condition for the while loop, then you will get the desired result

Answer 5

The value of dice is set only once, before the loop. A variable retains its value unless you explicitly change it.

What you could do is create a small function to use for a dice roll. It saves you from having to type out the code in the function more than once:

let dice = () => {return Math.floor(Math.random() * 6) + 1;}

roll = dice(); /* Set the initial value of roll */
while (roll !== 6) {
    console.log(`You rolled a ${roll}`);
    roll = dice(); /* Set the value for the next time round in the loop */
}

Notice that the call to the function has parentheses () to make it evaluate the function.