Javascript 正则表达式在文本被引号包围时用新行拆分字符串

Question

I want to use the split string method to split a string when a text is quoted. For example, I want this string:

Some text  

"This is what
I want to catch"

Some more text

To become a string array such as:

0: "Some text"
1: "This is what↵I want to catch"
2: "↵↵Some more text"

To achieve that, I am calling:

inputText.split(/"((.+)|\s)+"/)

This doesn't work as it creates the array:

0: "Some text"
1: "I want to catch"
2: "I want to catch"
3: "↵↵Some more text"

Any idea how to achieve what I want?

I cannot use look-behinds and look-aheads, because I still want the quotes to be a part of the match. My goal is to split the string when a text is surrounded by quotes, but not have the quotes themselves in the array.

Answer 1

As desired you may use this regex in split :

/\n*(?:"([^"\\]*(?:\\.[^"\\]*)*)")?\n+/

RegEx Explanation:

• \n* : Match 0+ line breaks
• (?: : Start non-capture group
  • " : Match opening "
  • ( : Start capture group
    • [^"\\]* : match 0+ of any characters that are not " and not \
    • (?:\\.[^"\\]*)* : Match an escaped character followed by 0+ of any characters that are not " and not \ . Repeat this group 0 or more times
  • ) : End capture group #1
  • " : Match closing "
• )? : End non-capture group. ? makes this group optional
• \n+ : Match 1+ line breaks

Code:

 const s = `Some text "This is what I want to catch" Some more text` var m = s.split(/\n*(?:"([^"\\]*(?:\\.[^"\\]*)*)")?\n+/) console.log(m)

---

Alternatively , you may use this regex in Javascript to match quoted string that allows escaping of quotes as well:

/"[^"\\]*(?:\\.[^"\\]*)*"|[^"\n]+/g

RegEx Demo

RegEx Explanation:

• " : match opening "
• [^"\\]* : match 0+ of any characters that are not " and not \
• (?:\\.[^"\\]*)* : Match an escaped character followed by 0+ of any characters that are not " and not \ . Repeat this group 0 or more times
• " : Match closing "
• | : OR
• [^"\n] : Match other lines without newline or "

Code:

 const s = `Some text "This is what I want to catch" Some more text` var m = s.match(/"[^"\\]*(?:\\.[^"\\]*)*"|[^"\n]+/g) console.log(m)

Answer 2

You can simply split over " . You can also truncate the leading and trailing new line characters.

 const s = `Some text "This is what I want to catch" Some more text` console.log(s.split('"'))