[英]Extract matching substrings from a list to new list in Python
I have a text file that looks like this:我有一个如下所示的文本文件:
garbage
moregarbaged89849843
MDeduri09ri44830
Some short sentence
Whatever ... key: d11001bfa937eee2f84f55a11b207356 (KID=01002d737832455680cffbadf1092baf)
Whatever2 ... key: a0ee2d0f8272355f750c5434db85291a (KID=0101bfa0ab9641a0b863ef76519a48d3)
Whatever3 ... key: fe216ba17e5af807ce5af8e43cf3c031 (KID=0102900a2bc54111833631ea7bb855ed)
77EB0A2C7C42EDC27A3D26E72A02BB29:01002d737832455680cffbadf1092baf status 'garbage'
blah blah:0101bfa0ab9641a0b863ef76519a48d3 has status 'usable'
77EB0A2C7C42EDC27A3D26E72A02BB29:blah blah
I only care about the key and KID parts, and want to extract them to separate lists我只关心 key 和 KID 部分,并想将它们提取到单独的列表中
My regex for that is key: (\w|\d){30,}
and KID=(\w|\d){30,}
respectively.我的正则表达式是
key: (\w|\d){30,}
和KID=(\w|\d){30,}
分别。
Code I'm using is我正在使用的代码是
matchkid = re.compile('KID=(\w|\d){30,}')
matchkey = re.compile('key: (\w|\d){30,}')
filteredkids = [a for a in lis if matchkid.search(a)]
filteredkeys = [b for b in lis if matchkey.search(b)]
print(filteredkids)
print('\n')
print(filteredkeys)
Where lis
is a list made from the lines of the text document其中
lis
是由文本文档的行组成的列表
The output is output 是
['Whatever ... key: d11001bfa937eee2f84f55a11b207356 (KID=01002d737832455680cffbadf1092baf)', 'Whatever2 ... key: a0ee2d0f8272355f750c5434db85291a (KID=0101bfa0ab9641a0b863ef76519a48d3)', 'Whatever3 ... key: fe216ba17e5af807ce5af8e43cf3c031 (KID=0102900a2bc54111833631ea7bb855ed)']
['Whatever ... key: d11001bfa937eee2f84f55a11b207356 (KID=01002d737832455680cffbadf1092baf)', 'Whatever2 ... key: a0ee2d0f8272355f750c5434db85291a (KID=0101bfa0ab9641a0b863ef76519a48d3)', 'Whatever3 ... key: fe216ba17e5af807ce5af8e43cf3c031 (KID=0102900a2bc54111833631ea7bb855ed)']
Which is wrong, the desired output is这是错误的,所需的 output 是
['KID=01002d737832455680cffbadf1092baf', 'KID=0101bfa0ab9641a0b863ef76519a48d3', 'KID=0102900a2bc54111833631ea7bb855ed']
['key: d11001bfa937eee2f84f55a11b207356', 'key: a0ee2d0f8272355f750c5434db85291a', 'key: fe216ba17e5af807ce5af8e43cf3c031']
I have tried tweaking my regex and looking at other similar questions, but nothing seems to work and most of the time I just get empty lists.我曾尝试调整我的正则表达式并查看其他类似的问题,但似乎没有任何效果,而且大多数时候我只是得到空列表。
Hoping to find some guidance here, thanks in advance希望在这里找到一些指导,在此先感谢
The (\w|\d){30,}
is not a good pattern as it creates a repeated capturing group, and is redundant itself: \w
matches digits, too, so \w{30,}
is enough. (\w|\d){30,}
不是一个好的模式,因为它创建了一个重复的捕获组,并且本身是多余的: \w
也匹配数字,所以\w{30,}
就足够了。
Next, you are using re.search
that only returns a Match data object, and you use listeneing comprehension to iterate over that object, while you need to grab all matches from your strings.接下来,您将使用仅返回匹配数据 object 的
re.search
,并使用侦听理解来迭代该 object,同时您需要从字符串中获取所有匹配项。
You can fix the code by using您可以使用以下方法修复代码
filteredkids = re.findall(r'KID=\w{30,}', text)
filteredkeys = re.findall(r'key: \w{30,}', text)
See the Python demo :请参阅Python 演示:
import re
text = """garbage
moregarbaged89849843
MDeduri09ri44830
Some short sentence
Whatever ... key: d11001bfa937eee2f84f55a11b207356 (KID=01002d737832455680cffbadf1092baf)
Whatever2 ... key: a0ee2d0f8272355f750c5434db85291a (KID=0101bfa0ab9641a0b863ef76519a48d3)
Whatever3 ... key: fe216ba17e5af807ce5af8e43cf3c031 (KID=0102900a2bc54111833631ea7bb855ed)
77EB0A2C7C42EDC27A3D26E72A02BB29:01002d737832455680cffbadf1092baf status 'garbage'
blah blah:0101bfa0ab9641a0b863ef76519a48d3 has status 'usable'
77EB0A2C7C42EDC27A3D26E72A02BB29:blah blah"""
filteredkids = re.findall(r'KID=\w{30,}', text)
filteredkeys = re.findall(r'key: \w{30,}', text)
print( filteredkids )
print( filteredkeys )
Output: Output:
['KID=01002d737832455680cffbadf1092baf', 'KID=0101bfa0ab9641a0b863ef76519a48d3', 'KID=0102900a2bc54111833631ea7bb855ed']
['key: d11001bfa937eee2f84f55a11b207356', 'key: a0ee2d0f8272355f750c5434db85291a', 'key: fe216ba17e5af807ce5af8e43cf3c031']
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