如何在 javascript 中的数组 object 的数组中搜索？

Question

I have a booking array of arrays that contain objects and I have to search inside the array using searchValue could you please help me here

here we have to check the booking id if booking id and searchValue matched we have to push that object into result array.

 let bookingArr = [ [{ name: "user 1", bookingid: 10, product: "ab" }, { name: "user 1", bookingid: 10, product: "cd" } ], [{ name: "user 2", bookingid: 11, product: "ui" }, { name: "user 1", bookingid: 10, product: "ef" } ], [{ name: "user 3", bookingid: 12, product: "ui" }, { name: "user 4", bookingid: 13, product: "ef" } ] ]; var searchValue = "10,11"; var FOUND = bookingArr.find(function(post, index) { if (post.bookingid == 11) return true; }); console.log(FOUND)

expected result

[ { name:"user 1", bookingid:10, product: "ab" },
    { name:"user 1", bookingid:10, product: "cd" },
    { name:"user 1", bookingid:10, product: "ef" },
    { name:"user 2", bookingid:11, product: "ui" }]

Answer 1

You can try this code:

 const bookingArr = [[ { name: 'user 1', bookingid: 10, product: 'ab' }, { name: 'user 1', bookingid: 10, product: 'cd' }, ], [ { name: 'user 2', bookingid: 11, product: 'ui' }, { name: 'user 1', bookingid: 10, product: 'ef' }, ], [ { name: 'user 3', bookingid: 12, product: 'ui' }, { name: 'user 4', bookingid: 13, product: 'ef' }, ]]; const searchValue = '10,11'; const sv = searchValue.split(',').map(Number); const FOUND = bookingArr.flat().filter(({ bookingid }) => sv.includes(bookingid)); console.log(FOUND);

Answer 2

You can try this:

 let bookingArr = [ [ { name: 'user 1', bookingid: 10, product: 'ab' }, { name: 'user 1', bookingid: 10, product: 'cd' }, ], [ { name: 'user 2', bookingid: 11, product: 'ui' }, { name: 'user 1', bookingid: 10, product: 'ef' }, ], [ { name: 'user 3', bookingid: 12, product: 'ui' }, { name: 'user 4', bookingid: 13, product: 'ef' }, ], ]; var searchValue = '10,11'; var searchIds = searchValue.split(','); var FOUND = []; bookingArr.forEach((el) => { el.forEach((el2) => { searchIds.forEach((num) => { if (num == el2.bookingid) { FOUND.push(el2); } }); }); }); console.log(FOUND);

Answer 3

Following with filter and Set will work:-

 let bookingArr = [ [{ name: "user 1", bookingid: 10, product: "ab" }, { name: "user 1", bookingid: 10, product: "cd" } ], [{ name: "user 2", bookingid: 11, product: "ui" }, { name: "user 1", bookingid: 10, product: "ef" } ], [{ name: "user 3", bookingid: 12, product: "ui" }, { name: "user 4", bookingid: 13, product: "ef" } ] ]; var searchValue = "10,11"; function logic(arr, searchValue) { let searchInputs = searchValue.split(','); let searchSet = new Set(searchInputs.map(val => parseInt(val))); let output = bookingArr.flat().filter(curr => searchSet.has(curr.bookingid)) return output; } console.log(logic(bookingArr, searchValue));

Answer 4

You can use Array#filter with a Set for better performance after flattening the array.

 let bookingArr = [[ { name:"user 1", bookingid:10, product: "ab" }, { name:"user 1", bookingid:10, product: "cd" } ],[ { name:"user 2", bookingid:11, product: "ui" }, { name:"user 1", bookingid:10, product: "ef" } ], [ { name:"user 3", bookingid:12, product: "ui" }, { name:"user 4", bookingid:13, product: "ef" } ]]; let searchValue = "10,11"; let set = new Set(searchValue.split(",").map(Number)); // for faster lookup let res = bookingArr.flat().filter(x => set.has(x.bookingid)); console.log(res);

Answer 5

You can simply flatten the array and filter out the desired results. Also, I've create a Set out of the search value for making the code more performant.

 let bookingArr = [ [ { name: 'user 1', bookingid: 10, product: 'ab' }, { name: 'user 1', bookingid: 10, product: 'cd' }, ], [ { name: 'user 2', bookingid: 11, product: 'ui' }, { name: 'user 1', bookingid: 10, product: 'ef' }, ], [ { name: 'user 3', bookingid: 12, product: 'ui' }, { name: 'user 4', bookingid: 13, product: 'ef' }, ], ]; const searchValue = "10,11" const searchSet = new Set(searchValue.split(",")) const res = bookingArr.flat().filter(b => searchSet.has(String(b.bookingid))) console.log(res)