[英]keeping shared_ptr use_count() at 1
I was unable to find a similar question to this one, please direct me to one if I missed it, I am experimenting with smart pointers, and came to this scenario where I would like to keep the value returned by use_count()
in a shared_ptr object to 1 (to practice optimizing code).我找不到与这个类似的问题,如果我错过了,请指导我,我正在尝试智能指针,并遇到了这种情况,我想将
use_count()
返回的值保留在 shared_ptr object 为 1(练习优化代码)。 Here is a snippet I am working with:这是我正在使用的一个片段:
#include <iostream>
#include <memory>
#include <vector>
// testFunc: displays the use_count of each shared ptr in the list
void testFunc(const std::vector<std::shared_ptr<int>> &list) {
// reference each shared ptr in the list and display their use_count
for (auto &elem : list) {
std::cout << elem.use_count() << std::endl;
}
} // testFunc()
int main() {
// allocate shared ptr instance of an int
auto sharedTest = std::make_shared<int>(11);
// allocate another shared ptr instance of another int
auto anotherSharedTest = std::make_shared<int>(22);
// use std::move to prevent another copy of the shared ptrs from being created
testFunc({ std::move(sharedTest), std::move(anotherSharedTest) });
return 0;
} // main()
The output by this program is该程序的 output 是
2
2
since the use_count of both shared ptrs is 2. Can anyone show me why I cannot keep them at 1?因为两个共享ptrs的use_count都是2。谁能告诉我为什么我不能把它们保持在1? I suspect that "passing" the vector to
testFunc
is creating a copy of each shared ptr when the entire vector is being passed, however this surprises me since I am passing the vector by reference.我怀疑当传递整个向量时,将向量“传递”给
testFunc
会创建每个共享 ptr 的副本,但这让我感到惊讶,因为我通过引用传递向量。 Any input is greatly appreciated!非常感谢任何输入!
The problem is the temporary initializer_list<shared_ptr>
keeps a copy of the elements, and it lives until the end of the full-expression (the ;
).问题是临时
initializer_list<shared_ptr>
保留元素的副本,并且它一直存在到完整表达式( ;
)的末尾。
There isn't much you can do, an initializer_list
always stores its elements by copy.您无能为力,
initializer_list
总是通过副本存储其元素。
As a workaround, you can construct the vector beforehand:作为一种解决方法,您可以预先构造向量:
std::vector<std::shared_ptr<int>> list{std::move(sharedTest), std::move(anotherSharedTest)};
testFunc(list);
Should print 1 1
.应该打印
1 1
。
According to this answer , std::initializer_list only allows const access to its elements.根据这个答案, std::initializer_list 只允许 const 访问其元素。 This means that the std::vector constructor needs to copy all elements from the list (because move is non-const).
这意味着 std::vector 构造函数需要从列表中复制所有元素(因为 move 是非常量的)。
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