选择 object 属性的简写 - 结合 ES6 `Object Deconstruction` 和 `Object Property Value` 简写

Question

Following code outputs {name: "Bob", surname: "Smith"} and it works fine. I want to know can I make it shorter.

((person = { name: 'Bob', surname: 'Smith', age: 22, }) => {
    const {
        name, // (a) create variable from deconstructing
        surname,
    } = person;

    return {
        name, // (b) reuse variable as new object parameter name (and value)
        surname
    }
})();

Can I somehow merge object deconstruction to variables (a) with returning a new object with Object Property Value shorthand (b) ?

I use here shorthand but then its purpose is defeated by the need to manually re-use parameters. I want to mention the name or surname word in my function once not twice...

Answer 1

Destructure person in the function's declaration:

 const result = (({ name, surname } = { name: 'Bob', surname: 'Smith', age: 22, }) => ({ name, // (b) reuse variable as new object parameter name (and value) surname }))(); console.log(result);

Answer 2

You can not mention it at all

((person = { name: 'Bob', surname: 'Smith', age: 22, }) => {
    const {age,...ans} = person;
   return ans
})()