如何优化我的代码，使其可以有效运行？

Question

I'm trying to optimize my code so, it runs faster. This is part of the code but what it basically does is takes a bunch of data from a website, finds the specific value and then prints it in the console.log.

My goal is to optimize my code so, that my code and process time are shorter

 const result = await page.evaluate(() => { const tds = Array.from(document.querySelectorAll('.table-dark-row td b')) return tds.map(td => td.innerText) }); //fetches the data from an element from a website so = 'Shares outstanding:' + result[4]; sf = 'Shares Float:' + result[10]; shof = 'Short Float:' + result[16]; sr = 'Short Ratio:' + result[24]; console.log(so, sf, shof, sr); //await browser.close(); });

Answer 1

You actually don't fetch the page multiple times when you reference a result[i] , so no worries about include it multiple times.

You could refactor the page.evaluate to page.$$eval so it will be written more concisely. Note: you won't really notice the performance difference between the two, it will only look cleaner. $$eval runs the same JavaScript methods under the hood:

[...] runs Array.from(document.querySelectorAll(selector)) within the page and passes it as the first argument to pageFunction.

So you could use it like this:

const results = await page.$$eval('.table-dark-row td b', tds => tds.map(td => td.innerText))

If you experience poor performance it should be another part of the script.