当从定时器模块使用 default_timer 时，“output 时间的单位”是什么？

Question

I'm trying to find the time taken by this program ("Fibonacci series") to run.

from timeit import default_timer as timer
n=int(input())
start = timer()
li=[0,1,1]
if n==1:
    print(li[0])
elif n==2 or n==3:
    print(li[1])
else:
    for i in range(n-3):
        x=li[-1]+li[-2]
        li.append(x)
print(li[-1])
print("{}".format(timer()-start))

I give the input 100 and I get the output as

218922995834555169026
0.0004896000000371714

The first line is the Fibonacci answer and the second line is the time taken, I want to know what is the unit of this time? '0.0004896000000371714' what this value means?

Answer 1

It is in seconds; see docs: the default timer usually points to the time.perf_counter function. You can use time.perf_counter_ns for nanoseconds.

If you inspect timer you will see it is <function time.perf_counter> or some similar result.