如何在整个数据集中找到 column1 值超过 column1 平均值两倍的所有数据行？

Question

I am trying find all the data rows with column1 values more than twice the average column1 value across the dataset with the code below but it seems it's not correct data. Here is the code:

select *,column1 over() from databasetest.Table1
where column1 > (select 2*avg(column1) from databasetest.Table1)

And here is the sample output

As you can see, the column1 value is still less than the twice the average column1 value across the dataset. I thought this should retrieve columns with more than twice the average column1 value across the dataset. Did I do something wrong or I misunderstand something? Any help would be appreciated

Answer 1

If I understand correctly, you can use window functions:

select *
from (select t1.*, avg(column1) over () as avg_column1
      from databasetest.Table1 t1
     ) t1
where t1.column1 > 2 * avg_column1;