如何根据组内日期之间的差异更改列？

Question

This is probably a simple problem but I am quite a noob in SQL. I am using Impala. So I have data like this:

New_ID	Date	Old_ID
1	2020-11-14 12:41:21	0
1	2020-11-14 12:50:40	1
2	2020-10-14 15:22:00	1.5
2	2020-12-18 11:31:05	2
3	2020-11-14 12:42:25	3

Assuming that I group by New_ID, I need to check that the difference between the date and the date immediately following it (if one exists) is less that 2 months (just gonna assume that's 60 days). If the difference is greater than 2 months then I need to change the New_ID to Old_ID. If it's less than or equal to 2 months, then the New_ID can remain the same. Essentially, I would like the new table to look like this:

New_ID	Date	Old_ID
1	2020-11-14 12:41:21	0
1	2020-11-14 12:50:40	1
1.5	2020-10-14 15:22:00	1.5
2	2020-12-18 11:31:05	2
3	2020-11-14 12:42:25	3

I have tried this code snippit and variations of it, but 1. I am not sure how to handle null values and 2. I keep getting a syntax error 'could not resolve column/field reference 'day' '

SELECT New_ID, Old_ID, Date,
LAG(Date) OVER(partition by New_ID ORDER BY Date) as previous_date,
case when datediff(day, previous_date, Date)/30.0 >= 2 then Old_ID
else New_ID end as 'new_identifier'
From MYTABLE;

Any pointers/suggestions would be greatly appreciated.

Answer 1

The Impala date function is months_between() -- and previous_date is not recognized so you need to repeat the expression:

SELECT New_ID, Old_ID, Date,
       LAG(Date) OVER (partition by New_ID ORDER BY Date) as previous_date,
       (case when months_between(date, LAG(Date) OVER (partition by New_ID ORDER BY Date)) >= 2 then Old_ID
             else New_ID
         end) as new_identifier
From MYTABLE;