如何从 javascript 中的字符串数组中删除特定字符串之后的所有内容

Question

I have an array of strings from which I want to remove anything after with in the statement. For example, let's take a string

var str = ['hey what is with you guys',
'you mean with out', 
'hello no with is you']

the new str2 should return

['hey what is', 
'you mean' ,
'hello no'
] 

I have written the following code but it is not giving the desirable output. My code:

function newArray(str){
    for (var i = 0; i <= (str.length - 1); i++){
        var k = str[i].toString()
        j = k.split('with')
        var arr2 = []
        var newArr = arr2.concat(j[0])
        console.log(newArr)
        
    }
    return newArr
}


var str = ['hey what is with you guys',
'you mean with out', 
'hello no with is you']

newArray(str)

the output is

[ 'hey what is ' ]
[ 'you mean ' ]
[ 'hello no ' ]

However, I want my output

['hey what is', 
'you mean' ,
'hello no'
] 

Answer 1

I do not see any reason to split the strings into arrays and then join them back into strings; you could manage everything using methods of the String object:

"modern" ES6+ solution

 function newStrings(arr, str) { return arr.map(string => { const index = string.indexOf(str); return index > 0? string.substr(0, index).trim(): string; }) } //test const original = [ 'hey what is with you guys', 'you mean with out', 'hello no with is you' ]; const modified = newStrings(original, 'with') console.log('original:', original); console.log('modified', modified);

"classic" solution

 function newStrings(arr, str) { var output = []; for (var i = 0; i < arr.length; i++) { var myString = arr[i]; var index = myString.indexOf(str); var outStr = index > 0? myString.substr(0, index).trim(): myString; output.push(outStr); } return output } //test var original = [ 'hey what is with you guys', 'you mean with out', 'hello no with is you' ]; var modified = newStrings(original, 'with') console.log('original:', original); console.log('modified', modified);

Answer 2

Here is a solution proposal, using ES6 Features such as Array.map

const str = [
  'hey what is with you guys',
  'you mean with out',
  'hello no with is you',
];

function removeWith(arr) {
  // Creates an array from an input array
  return arr.map((line) => {
    // For each line, split the string with the word "with"
    // I use a Regex with the `insensitive` flag to make it case insensitive.
    // So it works with "with" and "With" and "wiTH" ...
    return line.split(/with/i)[0];
    // [0] will return the first part of the string, even if nothing was split.
  });
}

Answer 3

you can try this and it worked.

 var str = ['hey what is with you guys', 'you mean with out', 'hello no with is you'] let arr2 = [] function newArray(str){ for (var i = 0; i <= (str.length - 1); i++){ var k = str[i].toString() let j = k.split('with') arr2.push(j[0]) } return arr2; } let ans = newArray(str); console.log(ans)