[英]PHP Trying to get property of a non-object
$sql = "select customer-name, customer-city from customer where customer-name in (select distinct customer-name from depositor, account where depositor.account-number=account.account-number and account.branch-name='Downtown')";
$result = $conn->query($sql);
if ($result->num_rows > 0) { //LINE 18
// output result in each row
while($row = $result->fetch_assoc()) {
echo "Name: ". $row['customer-name']. " " . $row["customer-city"] . "<br>";
}
} else {
echo "0 results";
}
The error I get:我得到的错误:
PHP Notice: Trying to get property of non-object in line 18
I tried using an array and that did not work either, I got the same error.我尝试使用数组,但也没有用,我得到了同样的错误。
In the PDO call of query ( https://www.php.net/manual/en/pdo.query.php ), you can see the following: PDO::query() returns a PDOStatement object, or false on failure.
In the PDO call of query ( https://www.php.net/manual/en/pdo.query.php ), you can see the following: PDO::query() returns a PDOStatement object, or false on failure.
It means that if the query fails, you keep only a false
instead of the PDOStatement
object.这意味着如果查询失败,您只保留一个false
而不是PDOStatement
object。
$sql = "select customer-name, customer-city from customer where customer-name in (select distinct customer-name from depositor, account where depositor.account-number=account.account-number and account.branch-name='Downtown')";
$result = $conn->query($sql);
if ($result == false) {
echo "Query failed";
} else if ($result->num_rows > 0) {
// output result in each row
while($row = $result->fetch_assoc()) {
echo "Name: ". $row['customer-name']. " " . $row["customer-city"] . "<br>";
}
} else {
echo "0 results";
}
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