汇编中的偏移量代表地址还是位？

Question

I am a bit confused, will inc [esi + 8] (lets say [esi] points to 0x0000001F in 8-bit memory) increment 0x00000027 or will it affect 0x00000020? I have seen a video implying it will affect the latter whereas regular pointers in ram go by addresses, not bits.

Answer 1

Addresses are bytes. This will increment 0x00000027 .

This doesn't assemble because you're missing the size though. inc {byte|word|dword|qword} ptr [esi + 8] is what you want. (Operand size is required)